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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections for questions 1 to 5: A team of 5 players Arun, Bilal, Chetan, Dalbir and Ellan participated in a ‘Cricket’ tournament and played four matches (1 to 4). The following table gives partial information about their individual scores and the total runs scored by the team in each match.
Each column has two values missing. These are the runs scored by the two lowest scorers in that match. None of the two missing values is more than 10% of the total runs scored in that match.
Figure:
What could be the possible runs scored by Arun and Bilal in Match III?
Correct
Solution: In Match III total score is 240, Chetan, Dalbir and Ellan together score 110+20+78= 208, Hence Arun and Bilal should together score 240208= 32. And also none (Arun and Bilal) should individually score more than 10% of total 240 runs i.e. 24 runs. Since option (b) satisfies all the condition, it is the answer.
Incorrect
Solution: In Match III total score is 240, Chetan, Dalbir and Ellan together score 110+20+78= 208, Hence Arun and Bilal should together score 240208= 32. And also none (Arun and Bilal) should individually score more than 10% of total 240 runs i.e. 24 runs. Since option (b) satisfies all the condition, it is the answer.

Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections for questions 1 to 5: A team of 5 players Arun, Bilal, Chetan, Dalbir and Ellan participated in a ‘Cricket’ tournament and played four matches (1 to 4). The following table gives partial information about their individual scores and the total runs scored by the team in each match.
Each column has two values missing. These are the runs scored by the two lowest scorers in that match. None of the two missing values is more than 10% of the total runs scored in that match.
Figure:
What could be the maximum possible runs scored by Ellan?
Correct
Solution: Since the missing values cannot be greater than 10% of the total runs scored in that match hence maximum possible runs for Ellan is 60 +30 + 78 + 20 = 188.
Incorrect
Solution: Since the missing values cannot be greater than 10% of the total runs scored in that match hence maximum possible runs for Ellan is 60 +30 + 78 + 20 = 188.

Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections for questions 1 to 5: A team of 5 players Arun, Bilal, Chetan, Dalbir and Ellan participated in a ‘Cricket’ tournament and played four matches (1 to 4). The following table gives partial information about their individual scores and the total runs scored by the team in each match.
Each column has two values missing. These are the runs scored by the two lowest scorers in that match. None of the two missing values is more than 10% of the total runs scored in that match.
Figure:
If the absolute difference between the total runs scored by Arun and Chetan in the four matches is minimum possible then what is the absolute difference between total runs scored by Bilal and Ellan in the four matches?
Correct
Solution: Maximum possible total runs scored by Chetan in the four matches = 27 + 30 + 110 + 20 = 187.In such a case minimum possible total runs scored by Arun in the four matches =23 + 100 + 13 + 53 = 189. Difference = 189 – 187 = 2 (minimum possible) subsequently total runs scored by Bilal in the four matches = 88 + 65 + 19 + 52 = 224.Also, total runs scored by Ellan in the four matches = 60 + 30 + 78 + 19 = 187, Absolute difference = 224 – 187 = 37
Incorrect
Solution: Maximum possible total runs scored by Chetan in the four matches = 27 + 30 + 110 + 20 = 187.In such a case minimum possible total runs scored by Arun in the four matches =23 + 100 + 13 + 53 = 189. Difference = 189 – 187 = 2 (minimum possible) subsequently total runs scored by Bilal in the four matches = 88 + 65 + 19 + 52 = 224.Also, total runs scored by Ellan in the four matches = 60 + 30 + 78 + 19 = 187, Absolute difference = 224 – 187 = 37

Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections for questions 1 to 5: A team of 5 players Arun, Bilal, Chetan, Dalbir and Ellan participated in a ‘Cricket’ tournament and played four matches (1 to 4). The following table gives partial information about their individual scores and the total runs scored by the team in each match.
Each column has two values missing. These are the runs scored by the two lowest scorers in that match. None of the two missing values is more than 10% of the total runs scored in that match.
Figure:
The players are ranked 1 to 5 on the basis of the total runs scored by them in the four matches, with the highest scorer getting Rank 1. If it is known that no two players scored the same number of total runs, how many players is there whose rank can be exactly determined?
Correct
Solution: Individual ranges for total score: Arpit> 189199, Bimal> 218224, Chatur> 182187, Dinu> 223, Elan> 187188. Least total will be of Chatur (Rank 5), 2nd least will be Elan (Rank 4), and Rank 3 must be of Arpit. It is not possible to determine the exact ranks of Bimal and Dinu.
Incorrect
Solution: Individual ranges for total score: Arpit> 189199, Bimal> 218224, Chatur> 182187, Dinu> 223, Elan> 187188. Least total will be of Chatur (Rank 5), 2nd least will be Elan (Rank 4), and Rank 3 must be of Arpit. It is not possible to determine the exact ranks of Bimal and Dinu.

Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections for questions 1 to 5: A team of 5 players Arun, Bilal, Chetan, Dalbir and Ellan participated in a ‘Cricket’ tournament and played four matches (1 to 4). The following table gives partial information about their individual scores and the total runs scored by the team in each match.
Each column has two values missing. These are the runs scored by the two lowest scorers in that match. None of the two missing values is more than 10% of the total runs scored in that match.
Figure:
What is the maximum possible percentage contribution of Arpit in the total runs scored in the four matches?
Correct
Solution: Maximum possible runs scored by Arpit in Match1 = 27, Maximum possible runs scored by Arpit in Match3 = 19, Maximum possible percentage contribution: ( 27+100+19+53)/(270+300+240+200)x100% =199/1010×100% = 19.7%
Incorrect
Solution: Maximum possible runs scored by Arpit in Match1 = 27, Maximum possible runs scored by Arpit in Match3 = 19, Maximum possible percentage contribution: ( 27+100+19+53)/(270+300+240+200)x100% =199/1010×100% = 19.7%

Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections for Question 68 : The questions consist of two statements numbered “I and II” given below it. You have to decide whether the data provided in the statement are sufficient to answer the questions?
If a real estate agent received a commission of 6 percent of the selling price of a certain house, what was the selling price of the house?
Statement I – The selling price minus the real estate agent’s commission was $84,600.
Statement II The selling price was 250 percent of the original purchase price of $36,000.Correct
Solution: From first statement it shows 94%= 84600 so, SP = 84600/94*100= 90000, From statement II SP = 36000/100*250 = 90000, hence both the statements individually are sufficient to answer the question.
Incorrect
Solution: From first statement it shows 94%= 84600 so, SP = 84600/94*100= 90000, From statement II SP = 36000/100*250 = 90000, hence both the statements individually are sufficient to answer the question.

Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections for Question 68 : The questions consist of two statements numbered “I and II” given below it. You have to decide whether the data provided in the statement are sufficient to answer the questions?
It is 8.00 p.m., when can Hemant get next bus for Ramnagar from Dhanpur?
Statement I: Buses for Ramnagar leave after every 30 minutes, till 10 p.m.
Statement II: Fifteen minutes ago, one bus has left for Ramnagar.Correct
Solution: Statement II reveals that the previous bus had left 7.45 p.m. As given in Statement I, the next bus would leave after 30 minutes i.e. at 8.15 p.m.
Incorrect
Solution: Statement II reveals that the previous bus had left 7.45 p.m. As given in Statement I, the next bus would leave after 30 minutes i.e. at 8.15 p.m.

Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections for Question 68 : The questions consist of two statements numbered “I and II” given below it. You have to decide whether the data provided in the statement are sufficient to answer the questions?
Is y an integer?
Statement I: y3 is an integer
Statement II: 3y is an integerCorrect
Solution: From statement I, we know that y3 is an integer. However, that does not necessarily mean that y is an integer. Let us say, y3 = 2, then y is not an integer. However, if y3 = 8, then y = 2 and is an integer. So, statement I alone is not sufficient. From statement II, we know that 3y is an integer. However, that does not necessarily mean that y is an integer. Let us say 3y = 2, then y is not an integer. However, if 3y = 3, then y will be an integer. Hence, statement II alone is also not sufficient. When we combine the two statements, we get that y3 is an integer and 3y is also an integer. Only for integer values of y, will both y3 and 3y simultaneously be integers. As both the statements together are needed to answer the question, choice (e) is the correct answer.
Incorrect
Solution: From statement I, we know that y3 is an integer. However, that does not necessarily mean that y is an integer. Let us say, y3 = 2, then y is not an integer. However, if y3 = 8, then y = 2 and is an integer. So, statement I alone is not sufficient. From statement II, we know that 3y is an integer. However, that does not necessarily mean that y is an integer. Let us say 3y = 2, then y is not an integer. However, if 3y = 3, then y will be an integer. Hence, statement II alone is also not sufficient. When we combine the two statements, we get that y3 is an integer and 3y is also an integer. Only for integer values of y, will both y3 and 3y simultaneously be integers. As both the statements together are needed to answer the question, choice (e) is the correct answer.

Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirection for Question 910: In the following question, two statements are numbered as I and II. On solving these statements you get Quantity I and Quantity II respectively. Solve for both the statements individually and mark the correct answer.
Quantity I: A man has Rs. 312 in the denominations of onerupee notes, fiverupee notes and twentyrupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has?
Quantity II: John gets on the elevator at the 14th floor of a building and rides up at the rate of 84 floors per minute. At the same time, Vinod gets on an elevator at the 58th floor of the same building and rides down at the rate of 92 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross?Correct
Solution: For Quantity I, Let number of notes of each denomination = x. Then x+5x+20x=312 ⇒26x=312 ⇒x=312/26=12 , Total number of notes =3x=3×12=36. For quantity II, Suppose their paths cross after x minutes. Then,
14+84x = 58−92x ⇒ 176x=44 ⇒x=44/176=1/4. Therefore, required floor
=14+84x=14+84×1/4= 35. Hence , Quantity I > Quantity II.Incorrect
Solution: For Quantity I, Let number of notes of each denomination = x. Then x+5x+20x=312 ⇒26x=312 ⇒x=312/26=12 , Total number of notes =3x=3×12=36. For quantity II, Suppose their paths cross after x minutes. Then,
14+84x = 58−92x ⇒ 176x=44 ⇒x=44/176=1/4. Therefore, required floor
=14+84x=14+84×1/4= 35. Hence , Quantity I > Quantity II. 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirection for Question 910: In the following question, two statements are numbered as I and II. On solving these statements you get Quantity I and Quantity II respectively. Solve for both the statements individually and mark the correct answer.
Quantity I: Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in?
Quantity II: A pump can fill a tank with water in 2 hours. Because of a leak, it took 2(1/3) hours to fill the tank. The leak can drain all the water of the tank in:Correct
Solution: From statement I, Net part filled in 1 hour = ( 1/5 + 1/6 – 1?12 ) = 17/60. Therefore the tank will be full in 60/17 hrs= 3 (9/17) hr. From statement II, Work done by the leak in 1 hour = (1/2 – 3/7)= 1/14. Therefore leak will empty the tank in = 14 hours. Hence Quantity I < Quantity II
Incorrect
Solution: From statement I, Net part filled in 1 hour = ( 1/5 + 1/6 – 1?12 ) = 17/60. Therefore the tank will be full in 60/17 hrs= 3 (9/17) hr. From statement II, Work done by the leak in 1 hour = (1/2 – 3/7)= 1/14. Therefore leak will empty the tank in = 14 hours. Hence Quantity I < Quantity II
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