# IBPS Clerk Prelims: Quants Day 4

Hello Aspirants. Welcome to Online Quant Section in AffairsCloud.com. We are starting IBPS Clerk course 2015 and we are creating sample questions in Quantitative Aptitude section, type of which will be asked in IBPS Clerk Prelims Exam.

Stratus – IBPS Clerk Course 2015 [flipclock]

1. Ratio of A’s age four years ago and B’s age four years ago was 5 : 8. A’s age 6 years after will be 6 less than B’s present age. Find the ratio of the present ages of A and B. A) 2 : 3 B) 3 : 4 C) 4 : 5 D) 5: 6 E) None of these
A) 2 : 3 Explanation: 4 yrs ago, A-4/B-4 = 5/8 8A – 5B = 12 After 6 yrs, A + 6 = B – 6 Solve the equations, A = 24, B = 36

2. A and B invested Rs 8,000 and Rs 9,000 in a business. After 4 months A withraw Rs 400 and B added Rs 400. What is the share of A from the profit of Rs 10,200? A) 5466 B) 5648 C) 4640 D) 4480 E) 4256
C) 4640 Explanation: 8000*4 + 7600*8 : 9000*4 + 9400*8 2 zeros get cancelled and 8 can be taken out in common from all terms. We are left with 40+76 : 45+94 116 : 139 Share of A = 116/(116+139) * 10200 = 4640

3. 5 men can complete a piece if work in 6 days. 3 women can complete the same work in 6 days. 2 men started the work and worked for 6 days. After this 6 women joined with them. In how many days the total work will be completed? A) 1 ½ days B) 2 ½ days C) 3 days D) 7 ½ days E) 8 days
D) 7 ½ days Explanation: 5 m in 6 days . So 2 m in 5*6/2 = 15 days. They work for 6 days. So they complete 1/15 * 6 = 2/5th of the work Now 2 m and 6 women have to complete remaining work ( 1 – 2/5) = 3/5 3 w in 6 days, so 6 w in 3*6/6 = 3 days 2m do in 15 days, 6 w in 3days so (2m + 6w)’s 1 day’s work = 1/15 + 1/3 = 6/15 = 2/5. Let (2m + 6w) complete remaining 3/5 th work in x days. So 2/5 * x = 3/5. x = 3/2 So total no of days to complete the work is 6 + 3/2 = 7 ½ days

4. The difference between compound interest and simple interest on a sum for 2 yrs at 10% per annum, when the interest is compounded annually is Rs 16. If the interest were compounded half yearly, the difference in two interests would be A) Rs 24.81 B) Rs 26.90 C) Rs 31.61 D) Rs 32.40 E) None of these
A) Rs 24.81

5. In a can, A and B are in the ratio 7 : 5. When 9 litres of mixture is drawn off and 9 litres of B is put in, the ratio of A : B becomes 7 : 9. How many litres of A was contained in the can initially? A) 20 B) 21 C) 25 D) 28 E) None of these
B) 21 Explanation: A = 7x litres, B = 5x litres After drawing off 9 litres, A left = 7x – 7/12 * 9 = (7x – 21/4) litres, B left = 5x – 5/12 * 9 = (5x – 15/4) litres After adding 9 litres of B, B becomes (5x – 15/4 + 9) litres Now, (7x – 21/4) / (5x – 15/4 + 9) = 7 / 9 Find x, x = 3, A contained in can = 7x = 21 litres

6. A gave 40% of amount to B. From this B gave 20% to C. From remaining B spends 40% on food and 20% of transport. Now he is left with Rs 912. Find the amount received by B. A) Rs 2890 B) Rs 2090 C) Rs 2270 D) Rs 2850 E) None of these
D) Rs 2850 Explanation: Let A has Rs x B gets 40/100 *x = 2/5 * x After giving 20% to C, B is left with 80/100 * 2/5 * x = 8/25 * x After spending 40% on food and 20% of transport, B left with 40/100 * 8/25 * x which is equal to 912 And we have to find 40/100 * x which equals 912 * 25/8 = 2850

7. A bag contains 3 white balls, 5 black balls and 4 yellow balls. 4 balls are drawn at random. What is the probability that there is one ball of each color? A) 5/22 B) 2/9 C) 8/11 D) 6/11 E) None of these
D) 6/11 Explanation: There are a total of 12 balls. Ways for drawing 4 balls is 12C4 = 12*11*10*9/4*3*2*1 = 495 Case 1 : 2 w balls, 1 b and 1 y Ways are 3C2*5C1*4C1=60 Case 2 : 1 w balls, 2 b and 1 y Ways are 3C1*5C2*4C1=90 Case 3 : 1 w balls, 1 b and 2 y Ways are 3C1*5C1*4C2=120 So total number of ways to draw 4 balls, 1 of each color = 60+90+120 = 270 So required prob. = 270/495 = 6/11

8. A shopkeeper sells 25 articles at Rs 45 per article after giving 10% discount and earns 50% profit. If the discount is not given, the profit gained is? A) 20% B) 25% C) 66 2/3% D) 13 1/3% E) None of these
C) 66 2/3% Explanation: Let MP = x SP of 1 article = 90/100 * x = 45, so x = 50 CP of 1 article = 100/150 * 45 = 30 If discount not given, SP = MP = 50, CP = 30, Find profit%

9. Volume of a right circular cone whose height is 21 m is 8800 cu. m. Find its curved surface area. A) 428ᴨ sq. m B) 580ᴨ sq. m C) 546ᴨ sq. m D) 480ᴨ sq. m E) None of these
B) 580ᴨ sq. m Explanation: 1/3 ᴨr2h = 8800 Put value of h, and find the value of r, r = 20 m Slant height, l = √ r2 + h2 l = √ 202 + 212 = 29 So CSA = ᴨrl = ᴨ*20*29 = 580ᴨ sq. m

10. A man covered a certain distance at some speed. Had he moved 3 km/hr faster, he would have taken 40 min less. If he had moved 2 km/hr slower, he would have taken 40 min more. The distance in km is A) 35 B) 36 C) 37 D) 40 E) None of these
D) 40 Explanation: For these types of ques, when u r not given actual speed, but given faster and slower speeds, use: Let faster speed = s1 = 3, slower speed = s2 = 2 Average speed of journey = 2* (s1*s2)/s1-s2 = 2* (3*2) /(3-2) = 12 km/hr Now distance = (s+s1) * (s-s2) / (s+s1) – (s-s2) * difference in times Here difference in times is 40 mins more – 40 mins early = 80 min = 80/60 hrs So, distance = (12+3) * (12-2) / (12+3) – (12-2) * 80/60 = 40 km

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