Hello Aspirants. Welcome to Online Quant Section in AffairsCloud.com. We are starting **IBPS Clerk course 2015 **and we are creating sample questions in **Quantitative Aptitude** section, type of which will be asked in IBPS Clerk Prelims Exam.

**Stratus – IBPS Clerk Course 2015 **

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**The ratio of the number of boys and girls in a school is 3 : 2. If 20% of the boys and 25% of the girls are scholarship holders, what percentage of the students does not get the scholarship?**

A) 72

B) 70

C) 56

D) 80

E) 78

E) 1/13

**B) 1/6**

Explanation:

Number of boys = 3x, number of girls = 2x

Boys that do not scholarship = 80/100 * 3x = 12x/5

Girls that do not scholarship = 75/100 * 2x = 3x/2

Total students who do not get sch. = 12x/5 + 3x/2 = 39x/10

% of students who do not get sch. = Total students who do not get sch./total students in school *100

= (39x/10) / 5x * 100 = 78%

**A committee of 4 is to be formed from among 4 girls and 5 boys. What is the probability that the committee will have number of boys less than number of girls?**

A) 1/12

B) 1/6

C) 1/10

D) 2/13

E) 1/13

**B) 1/6**

Explanation:

Case 1: 4 girls and 0 boys

4C4/9C4

Case 2: 3 girls and 1 boy

4C3*5C1/9C4

Total probability = 4C4/9C4 + 4C3*5C1/9C4

**How many bullets can be made out of a cylinder, 28 cm high and 6 cm radius, each bullet being 1.5 cm in diameter?**

A) 1582

B) 1600

C) 1678

D) 1790

E) None of these

**E) None of these**

Explanation:

Volume of cylinder = pie* r^{2}h = 22/7 * 6^{2}* 28

Volume of 1 bullet = 4/3 pie * r^{3}= 4/3 * 22/7 * 1.5^{3}

Number of bullets = Volume of cylinder / Volume of 1 bullet

**A jar contains a mixture of two liquids A and B in the ratio 3 : 2. When 10 litres of this mixture is taken out and 10 litres of liquid A is poured into the jar, the ratio becomes 11 : 4. How many litres of liquid A was contained in the jar?**

A) 18 litres

B) 15 litres

C) 12 litres

D) 10 litres

E) 18.3 litres

**A) 18 litres**

Explanation:

A is 3x litres and B is 2x litres

10 litres taken out

A left in mixture = 3x – 3/5 * 10 = (3x – 6) litres

B left in mixture = 2x – 2/5 * 10 = (2x – 4) litres

Now 10 litres poured, A becomes (3x – 6) +10 = (3x + 4) litres

New ratio is 11 : 4

So, 3x+4 / 2x-4 = 11/4, solve: x = 6

So A contained in jar = 3x = 3*6 = 18 litres

**A can do a piece of work in the same time in which B and C can together do it. If A and B can together do it in 10 days and C alone in 50 days, then B alone could do it in:**

A) 20 days

B) 22 days

C) 25 days

D) 28 days

E) None of these

**C) 25 days**

Explanation:

(A+B+C)’s 1 day’s work: 1/A + 1/B + 1/C = 1/10 + 1/50 = 3/25

Given 1/A = 1/B +1/C

So, 1/A +1/A = 3/25 gives 1/A = 3/50

1/A + 1/B = 1/10, so 1/B = 1/10 – 3/50 = 1/25

So B can do in 25 days

** Directions (Q. 6-10): Study the following table and graph and answer the following questions.**

**How many companies show a consistent increase or decrease in the sales of the cars during the given period?**

A) 0

B) 1

C) 2

D) 3

E) 4

**C) 2**

Explanation:

Bajaj Automobiles show constant decrease and Tata Motors show a constant increase in the line graph. So in total two.**If the selling price of one unit of car sold by Bajaj Automobiles is 3 lakhs and the cost of production of one unit of car by Bajaj Automobiles is 2.5 lakhs, then what is the total profit/loss incurred by Bajaj Automobiles during the given period?**

A) 300 crores profit

B) 300 crores loss

C) 250 crores profit

D) 250 crores loss

E) None of these

**A) 300 crores profit**

Explanation:

Total production of Bajaj Auto. (in thousands) = 76+65+60+35+24+20+20 = 300,000. So total CP = 300,000 * 2.5 lakhs = 75 * 10^{9}

Total sale of Bajaj Auto. (in thousands) = 70+60+55+30+20+15+10 = 260,000. So total SP = 260,000 * 3 lakhs = 78 * 10^{9}

Profit = 78 * 10^{9}– 75 * 10^{9}= 3 * 10^{9}

**In 2006, sales as a percentage of the production is maximum for which of the following companies?**

A) Maruti Udyog Ltd.

B) Bajaj Automobiles

C) Tata Motors

D) Hyundai

E) Honda

**B) Bajaj Automobiles**

Explanation:

For Hyundai = 90/100 * 100 = 90%

Maruti = 70/80 * 100 = 87.5%

Bajaj = 55/60 * 100 = 91.7%

Tata = 40/56 * 100 = 71.4%

Honda = 20/24 * 100 = 83.3%**Which of the following companies had the maximum percentage increase in the production of cars in 2009 as compared to the previous year?**

A) Maruti Udyog Ltd.

B) Bajaj Automobiles

C) Honda

D) Hyundai

E) Tata Motors

**C) Honda**

Explanation:

For Hyundai and Bajaj Auto there is decrease from 2008 to 2009.

Find for remaining three.

Maruti = 90-80/80 * 100 = 12.5%

Tata = 80-70/70 * 100 = 14.3%

Honda = 50-40/40 * 100 = 25%

So for Honda it is maximum.

**Note –**You can also find it by observing, since all have difference equal to 10. In the denominator the one having least number will have maximum %**What is the total number of cars sold in 2007?**

A) 2,50,000

B) 3,50,000

C) 2,00,000

D) 3,00,000

E) None of these

**D) 3,00,000**

Explanation:

90+80+60+40+30

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