Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From Data Interpretation that is important for all the competitive exams. We have included Some questions that are repeatedly asked in exams.
(Q.no: 1-5). Refer to the table and answer the given questions.
NA refers the data which is not needed for a particular question. The number of working days of A, B, C, D is given below and some of them are missing. Take the data of the first row for the first question and the second row for the second question and so on.
|A||B||C||D||Ratio||Total Number of Working Days|
|_||25||NA||NA||Efficiency (A : B) = 5 : 4||NA|
- A started a work alone and then B joined her 5 days before actual completion of the work. For how many days A worked alone?
E. 12Answer – B. 11
Efficiency (A : B) = 5 : 4
Number of days(A : B) = 4x : 5x = 4x : 25
∴ Number of days required by A to finish the work alone = 4x
= 4 x 5 = 20.
A and B work together for last 5 days = 5 x 9 = 45%
Efficiency of A = 5% and B’s efficiency = 4%
∴ No. of days taken by A to complete 55% work = 55/5 = 11days
- Working together B and C take 50% more number of days than A, B and C together take and A and B working together, take 8/3 more number of days than A, B and C take together. If A, B and C all have worked together till the completion of the work and B has received Rs.120 out of total earnings of Rs. 480 then in how many days did A, B and C together complete the whole work?
A. 2 days
B. 4 days
C. 6 days
D. 8 days
E. 5 daysAnswer – E. 5 days
The days ratio of (A + B + C) : (B + C) = X:3X/2 = 2X:3x;
Efficiency ratio = 3X:2X
Efficiency of A = x.
(480/3X) = Rs.160
Amount received by B = Rs.120 & C = 200
(1/15+1/12+1/20)*Y = 1
Y = 5 days
- All of them started to work together but A leaves after 4 days. B leaves the job 3 days before the completion of the work. How long would the work last?
A. 6 days
B. 9 days
C. 18 days
D. 5 days
E. None of theseAnswer – B. 9 days
Let the work lasted for x days,
A’s 4 day’s work + B (x – 3) day’s work + C’s x day’s work = 1
⇒ (4/16) + (x – 3) / (64/5) + x/32 = 1
⇒ 5(x – 3)/64 + x/32 = 1 – 1/4
⇒ [5(x – 3) + 2x] / 64 = 3/4
⇒ 7x – 15 = 48
∴ x = (48 + 15)/7 = 63/7 = 9 days
- C started the work and left after some days, when 25% work was done. After it D joined and completed it working for 25 days. In how many days C and D can do the complete work, working together?
E. 20Answer – E. 20
Efficiency of C = (100/50) = 2%
Rest work = 75%
∴ Efficiency of D = 75/25 = 3%
∴ Combined efficiency of C and D = 5%
∴ Number of days required by C and D to work together = 100/5 = 20 days.
- B and C started the work. After 3 days D joined them. What is the total number of days in which they had completed the work?
E. None of theseAnswer – C.4 days
Efficiency of B and C = 11.11 + 5.55 = 16.66%
Work done in 3 days = 3 x 16.66 = 50%
Rest work done by B, C and D = 50/50 = 1 day
Work can be completed in 4 days.
(Q.no: 6 -10). Refer to the table and answer the given questions.
NA refers the data which is not needed for a particular question. The price details of 5 products are given below and some of them are missing. Take the data of the first row for the first question and the second row for the second question and so on.
- Rahul purchased a mobile and sold it for a loss(loss % given in the table). From that money, he purchased another article and sold it for a gain of (Profit % given in the table). What is the overall gain or loss?
A. Profit of Rs.21
B. Profit of Rs.24
C. Loss of Rs.21
D. Loss of Rs.24
E. None of theseAnswer – C. Loss of Rs.21
CP = 8400
SP = 8400 * 95/100 = 7980
CP = 7980
SP = 7980 * 105/100 = 8379
Difference = 8400 – 8379 = 21
- A, B and C invests rupees 8000, 12000 and 10000 respectively in a business. At the end of the year the balance sheet shows a loss of initial investment. Find the share of loss of B.
E.None of theseAnswer – C.4800
Total loss after one year = 30000*40/100 = 12000
share of B = (40/10)*12000 = 4800
- A Shop Keeper sells two bags for Rs. 500 each. On one, he gets % profit(as per the table) and on the other he gets % loss(as per the table). His profit or loss in the entire transaction was?
A. 64/25 % Gain
B. 49/25 % Gain
C. 64/25 % Loss
D. 49/25 % Loss
E. None of theseAnswer – D. 49/25 % Loss
% = x
Loss % = x²/100 = 196/100 = 49/25%
- The price of TV was marked up by %(as per the table).It was sold at a discount of 20% on the marked price. What was the profit percent of the cost price?
E. None of theseAnswer – D. 12%
40 – 20 + [40 * (-20)/100]
= 20 – 8 = 12%
- Preethi sold a machine to Shalini at a profit of %(as per table). Shalini sold this machine to Arun at a loss of %(as per table). If Preethi paid Rs.5000 for this machine, then find the cost price of machine for Arun?
E. None of theseAnswer – B. 5200
R1 = 30% R2 = 20%
5000 * 130/100 * 80/100 = Rs. 5200