Aptitude Questions: Quadratic Equations Set 11

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You have to solve equation I and II ,Give answer
1)If X>Y
2)If X<Y
3)If X≥ Y
4)If X≤ Y           
5)If X=Y or cannot be established

1. I.4/√x + 3/√x = √x
   II. Y² – (7 ^5/2/√y) = 0
   
   Answer & Explanation

   Answer – 5)If X=Y or cannot be established
   Explanation :
   7/√x = /√x
   X =7
   (Y^35/2 – 7 ^5/2 )/√y=0
   Y^5/2 =7 ^5/2
   y = 7   x=y
   
   
   
2. I. X^2/3  = 49
   II.Y =(-4)⁴
   
   Answer & Explanation

   Answer – 1)If X>Y
   Explanation :
   X = 7³ = 343
   Y = -4*-4*-4*-4 = 256
   x>y
   
   
   
3. I. X²  – 18X + 72= 0
   II.Y² – 20Y + 99 = 0
   
   Answer & Explanation

   Answer – 5)If X=Y or cannot be established
   Explanation :
   (x-12)(x-6) = 0
   X=6,12
   (y-11)(y-9) = 0
   Y=9,11
   12,11,9,6=> xyyx
   
   
   
4. I.X = ±√441
   II.Y = (9261)^1/3
   
   Answer & Explanation

   Answer – 4)If X≤ Y
   Explanation :
   X=±21
   Y = 21
   
   
   
5. I. X²  – 698  =  326
   II.Y² + 528 = 1552
   
   Answer & Explanation

   Answer – 5)If X=Y or cannot be established
   Explanation :
   X²  = 326+698 =1024
   Y²=1552 – 528 = 1024
   X=y = ±32
   
   
   
6. I. 2X² + 11X + 12= 0
   II.2Y² + 19Y + 45 = 0
   
   Answer & Explanation

   Answer – 1)If X>Y
   Explanation 
   (2x+8)(2x+3) = 0
   X= -8/2, -3/2 = -4,-1.5
   (2y+10)(2y+9) = 0
   Y= -10/2, -9/2 = -5, -4.5
   -1.5,-4,-4.5,-5 => xxyy
   x>y
   
   
   
7. I. 21X²  – 23X + 6= 0
   II.2Y² – 11Y + 15 = 0
   
   Answer & Explanation

   Answer – 2)If X<Y
   Explanation :
   (7x-3)(3x-2) = 0
   X=3/7, 2/3 = 0.43, 0.67
   (2y-5)(y-3) = 0
   Y=3,5/2=3,2.5
   3,5/2,2/3,3/7 => yyxx
   X<y
   
   
   
8. I. 3X²  + 10X + 8= 0
   II.3Y² + 7Y + 4 = 0
   
   Answer & Explanation

   Answer – 4)If X≤ Y
   Explanation :
   (3x+4)(x+2) = 0
   X= -2,-4/3
   (y+1)(3y+4) = 0
   Y= -1,-4/3
   -1,-1.3,-1.3,-2 => yyxx
   x≤y
   
   
   
9. I. 25X²  + 25X + 6= 0
   II.5Y² + 20Y + 20 = 0
   
   Answer & Explanation

   Answer – 1)If X>Y
   Explanation :
   (5x+2)(5x+3) =0
   X= -2/5, -3/5 = -0.4, -0.6
   (5x+10)(x+2) = 0
   X= -10/5, -2 = -2, -2
   -0.4, -0.6, -2, -2 => Xxyy
   X>y
   
   
   
10. I. 2X² + 5X + 2= 0
    II.4Y² – 1 = 0
    
    Answer & Explanation

    Answer – 4)If X≤ Y
    Explanation :
    (2x+1)(x+2) =0
    X= -1/2, -2
    Y²  = ±1/2 = ½, -1/2
    ½,-1/2,-1/2, -2
    yxxy
    
    
    

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