Hello Aspirants. Welcome to Online Maths in AffairsCloud.com. Here we are creating question sample in Compound Interest, which is common for all the IBPS, SBI exam and other competitive exams. We have included Some questions that are repeatedly asked in exams !!
Questions Penned by Yogit
- A sum of rupees 3903 is divided between P and Q such that the share of P at the end of 8 years is equal to the share of Q after 10 years. Find the share of P if rate of interest is 4% compounded annually.
a) 2012
b) 2029
c) 2028
d) 2081
e) None of theseAnswer –c) 2028
Explanation :
P*(1 + 4/100)^8 = (3903 – P)*(1 + 4/100)^10 -  A man borrows 2000 rupees at 10% compound interest. At the end every year he pays rupees 1000 back. How much amount should he pay at the end of the third Year to clear all his debt?
a) 252
b) 352
c) 452
d) 552
e) None of theseAnswer – b) 352
Explanation :
After one year amount = 2000*110/100 = 2200
He pays 1000 back, so remaining = 2200 – 1000 = 1200
After second year = 1200*110/100 = 1320
He pays 1000 back, so remaining = 1320 – 1000 = 320
After third year = 320*110/100 = 352 - A sum of rupees 3200 is compounded annually at the rate of 10 paisa per rupee per annum. Find the compound interest payable after 2 years.
a) 200
b) 842
c) 672
d) 832
e) None of theseAnswer – c) 672
Explanation :
Rate of interest is 10 paisa per rupee per annum. So for 100 rupees it is 1000 paise i.e. 10 percent
Now, CI = 3200(1+10/100)^ 2Â – 3200 = 672 - What sum of money will amount to rupees 1124.76 in 3 years, if the rate of interest is 5% for the first year, 4% for the second year and 3% for the third year?
a) 1500
b) 1200
c) 1000
d) 1900
e) None of theseAnswer – c) 1000
Explanation :
1124.76 = p*(105/100)*(104/100)*(103/100) - Riya saves an amount of 500 every year and then lent that amount at an interest of 10 percent compounded annually. Find the amount after 3 years.
a) 1820.5
b) 1840.5
c) 1920.5
d) 1940.5
e) None of theseAnswer – a) 1820.5
Explanation :
Total amount = 500*(1+10/100)^ 3 + 500*(1+10/100)^ 2 + 500*(1+10/100) = 1820.5 - A sum of 3000 becomes 3600 in 3 years at 15 percent per annum. What will be the sum at the same rate after 9 years?
a) 5124
b) 5184
c) 5186
d) 5192
e) None of theseAnswer – b) 5184
Explanation :
3600 = 3000*(1+15/100)^ 3
(1+15/100)^ 3 = 6/5
Amount = 3000*[(1+15/100)^ 3]^ 3
Amount = 3000*(6/5)^3 = 5184 - On a certain sum of money, after 2 years the simple interest and compound interest obtained are Rs 400 and Rs 600 respectively. What is the sum of money invested?
a) 100
b) 200
c) 300
d) 400
e) None of theseAnswer –b) 200
Explanation :
400 = P*(R/100)*2
600 = P*(1+R/100)^2 – P
Solve both equations to get P - A sum of money becomes Rs 35,280 after 2 years and Rs 37,044 after 3 years when lent on compound interest. Find the principal amount.
a) 2800
b) 3000
c) 3200
d) 4000
e) None of theseAnswer –c) 3200
Explanation :
37044 = p*(1 +r/100)^3
35280 = p*(1 + r/100)^2
Divide both equations to get the value of r and then substitute in any equation to get P - A sum of money is lent for 2 years at 10% p.a. compound interest. It yields Rs 8.81 more when compounded semi-annually than compounded annually. What is the sum lent?Â
a) 1000
b) 1200
c) 1400
d) 1600
e) None of theseAnswer – d) 1600
Explanation :
8.81 = p*(1+5/100)^4 – p*(1+10/100)^2 - A sum of rupees 4420 is to be divided between raj and parth in such a way that after 5 years and 7 years respectively the amount they get is equal. The rate of interest is 10 percent. Find the share of raj and parth
a) 2000, 2420
b) 2420, 2000
c) 2480, 2420
d) 2210, 2210
e) None of theseAnswer – b) 2420, 2000
Explanation :
Let the share of raj and parth be R and P
R*(1+10/100)^ 5 = (4420 – R)*(1+10/100)^ 7
We get R = 2420, so P = 2000
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