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IBPS Clerk Prelims: Quants Day 11

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Hello Aspirants. Welcome to Online Quant Section in AffairsCloud.com. We are starting IBPS Clerk course 2015 and we are creating sample questions in Quantitative Aptitude section, type of which will be asked in IBPS Clerk Prelims Exam.

Stratus – IBPS Clerk Course 2015 

Stratus - IBPS Clerk - Daily Test - Quants
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  1. The ratio of the number of boys and girls in a school is 3 : 2. If 20% of the boys and 25% of the girls are scholarship holders, what percentage of the students does not get the scholarship?
    A) 72
    B) 70
    C) 56
    D) 80
    E) 78
    E) 1/13
    B) 1/6
    Explanation:
    Number of boys = 3x, number of girls = 2x
    Boys that do not scholarship = 80/100 * 3x = 12x/5
    Girls that do not scholarship = 75/100 * 2x = 3x/2
    Total students who do not get sch. = 12x/5 + 3x/2 = 39x/10
    % of students who do not get sch. = Total students who do not get sch./total students in school *100
    = (39x/10) / 5x * 100 = 78%

  2. A committee of 4 is to be formed from among 4 girls and 5 boys. What is the probability that the committee will have number of boys less than number of girls?
    A) 1/12
    B) 1/6
    C) 1/10
    D) 2/13
    E) 1/13
    B) 1/6
    Explanation:
    Case 1: 4 girls and 0 boys
    4C4/9C4
    Case 2: 3 girls and 1 boy
    4C3*5C1/9C4
    Total probability = 4C4/9C4 + 4C3*5C1/9C4

  3. How many bullets can be made out of a cylinder, 28 cm high and 6 cm radius, each bullet being 1.5 cm in diameter?
    A) 1582
    B) 1600
    C) 1678
    D) 1790
    E) None of these
    E) None of these
    Explanation:
    Volume of cylinder = pie* r2h = 22/7 * 62 * 28
    Volume of 1 bullet = 4/3 pie * r3 = 4/3 * 22/7 * 1.53
    Number of bullets = Volume of cylinder / Volume of 1 bullet

  4. A jar contains a mixture of two liquids A and B in the ratio 3 : 2. When 10 litres of this mixture is taken out and 10 litres of liquid A is poured into the jar, the ratio becomes 11 : 4. How many litres of liquid A was contained in the jar?
    A) 18 litres
    B) 15 litres
    C) 12 litres
    D) 10 litres
    E) 18.3 litres
    A) 18 litres
    Explanation:
    A is 3x litres and B is 2x litres
    10 litres taken out
    A left in mixture = 3x – 3/5 * 10 = (3x – 6) litres
    B left in mixture = 2x – 2/5 * 10 = (2x – 4) litres
    Now 10 litres poured, A becomes (3x – 6) +10 = (3x + 4) litres
    New ratio is 11 : 4
    So, 3x+4 / 2x-4 = 11/4, solve: x = 6
    So A contained in jar = 3x = 3*6 = 18 litres

  5. A can do a piece of work in the same time in which B and C can together do it. If A and B can together do it in 10 days and C alone in 50 days, then B alone could do it in:
    A) 20 days
    B) 22 days
    C) 25 days
    D) 28 days
    E) None of these
    C) 25 days
    Explanation:
    (A+B+C)’s 1 day’s work: 1/A + 1/B + 1/C = 1/10 + 1/50 = 3/25
    Given 1/A = 1/B +1/C
    So, 1/A +1/A = 3/25 gives 1/A = 3/50
    1/A + 1/B = 1/10, so 1/B = 1/10 – 3/50 = 1/25
    So B can do in 25 days

Directions (Q. 6-10): Study the following table and graph and answer the following questions.11-1-daily

11-2-daily

  1. How many companies show a consistent increase or decrease in the sales of the cars during the given period?
    A) 0
    B) 1
    C) 2
    D) 3
    E) 4
    C) 2
    Explanation:
    Bajaj Automobiles show constant decrease and Tata Motors show a constant increase in the line graph. So in total two.

  2. If the selling price of one unit of car sold by Bajaj Automobiles is 3 lakhs and the cost of production of one unit of car by Bajaj Automobiles is 2.5 lakhs, then what is the total profit/loss incurred by Bajaj Automobiles during the given period?
    A) 300 crores profit
    B) 300 crores loss
    C) 250 crores profit
    D) 250 crores loss
    E) None of these
    A) 300 crores profit
    Explanation:
    Total production of Bajaj Auto. (in thousands) = 76+65+60+35+24+20+20 = 300,000. So total CP = 300,000 * 2.5 lakhs = 75 * 109
    Total sale of Bajaj Auto. (in thousands) = 70+60+55+30+20+15+10 = 260,000. So total SP = 260,000 * 3 lakhs = 78 * 109
    Profit = 78 * 109 – 75 * 109 = 3 * 109

  3. In 2006, sales as a percentage of the production is maximum for which of the following companies?
    A) Maruti Udyog Ltd.
    B) Bajaj Automobiles
    C) Tata Motors
    D) Hyundai
    E) Honda
    B) Bajaj Automobiles
    Explanation:
    For Hyundai = 90/100 * 100 = 90%
    Maruti = 70/80 * 100 = 87.5%
    Bajaj = 55/60 * 100 = 91.7%
    Tata = 40/56 * 100 = 71.4%
    Honda = 20/24 * 100 = 83.3%

  4. Which of the following companies had the maximum percentage increase in the production of cars in 2009 as compared to the previous year?
    A) Maruti Udyog Ltd.
    B) Bajaj Automobiles
    C) Honda
    D) Hyundai
    E) Tata Motors
    C) Honda
    Explanation:
    For Hyundai and Bajaj Auto there is decrease from 2008 to 2009.
    Find for remaining three.
    Maruti = 90-80/80 * 100 = 12.5%
    Tata = 80-70/70 * 100 = 14.3%
    Honda = 50-40/40 * 100 = 25%
    So for Honda it is maximum.
    Note – You can also find it by observing, since all have difference equal to 10. In the denominator the one having least number will have maximum %

  5. What is the total number of cars sold in 2007?
    A) 2,50,000
    B) 3,50,000
    C) 2,00,000
    D) 3,00,000
    E) None of these
    D) 3,00,000
    Explanation:
    90+80+60+40+30





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