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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). Five companies A, B, C, D and E offer different interest rates for different amount of investments as shown by the following table. Read it carefully and answers the following questions.**

**A person invested Rs 55000 in the company B for two years at compound interest and after that in company C for three years at simple interest. How much amount will he have after 5 years?**Correct**Answer- 4) Rs 69733.125**

Explanation-

Amount he will get from company B after two years = 105/100 ×105/100 × 55000 = Rs 60637.5

Amount he will get after investing this amount in company D for three years = 115/100 × 60637.5 = 1.15 × 60637.5 = Rs 69733.125Incorrect**Answer- 4) Rs 69733.125**

Explanation-

Amount he will get from company B after two years = 105/100 ×105/100 × 55000 = Rs 60637.5

Amount he will get after investing this amount in company D for three years = 115/100 × 60637.5 = 1.15 × 60637.5 = Rs 69733.125 - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). Five companies A, B, C, D and E offer different interest rates for different amount of investments as shown by the following table. Read it carefully and answers the following questions.**

**Sohan invested Rs 45000 in company C for three years at simple interest and then in company D for three years at compound interest. What is the difference between the amount he will get after six years and amount he invested initially?**Correct**Answer- 2) 13344.3**

Explanation-

Amount Sohan will receive after three years from company C = 112/100 × 45000 = Rs 50400

Amount Sohan will receive after further three years after investing in company D = 115.7625/100 × 50400 = Rs 58344.3 (the interest rate will be 5% in this case since the amount in more than Rs 50000)

Required difference = 58344.3 – 45000 = Rs 13344.3Incorrect**Answer- 2) 13344.3**

Explanation-

Amount Sohan will receive after three years from company C = 112/100 × 45000 = Rs 50400

Amount Sohan will receive after further three years after investing in company D = 115.7625/100 × 50400 = Rs 58344.3 (the interest rate will be 5% in this case since the amount in more than Rs 50000)

Required difference = 58344.3 – 45000 = Rs 13344.3 - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). Five companies A, B, C, D and E offer different interest rates for different amount of investments as shown by the following table. Read it carefully and answers the following questions.**

**An amount of Rs 19700 was invested in company D for three years at compound interest (the amount is transferred to higher interest rate scheme when it crosses Rs 20000). What is the total interest earned on the amount?**Correct**Answer- 4) Rs 2458.8349**

Explanation-

Amount after 1 year = 19700 + 3.2% of 19700 = 19700 + 630.4 = Rs 20330.4

Amount after 2 years = 20330.4 + 4.4% of 20330.4 = 20330.4 + 894.5376 = Rs 21224.9376

Amount after 3 years = 21224.9376 + 4.4% of 21224.9376 = 21224.9376 + 933.897254 = Rs 22158.8349

Compound interest = 22158.8349 – 19700 = Rs 2458.8349Incorrect**Answer- 4) Rs 2458.8349**

Explanation-

Amount after 1 year = 19700 + 3.2% of 19700 = 19700 + 630.4 = Rs 20330.4

Amount after 2 years = 20330.4 + 4.4% of 20330.4 = 20330.4 + 894.5376 = Rs 21224.9376

Amount after 3 years = 21224.9376 + 4.4% of 21224.9376 = 21224.9376 + 933.897254 = Rs 22158.8349

Compound interest = 22158.8349 – 19700 = Rs 2458.8349 - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude

**An amount of more than 1 lakh was invested in company E at compound interest for two years. What was the amount invested if the interest earned is Rs 20790.77?**Correct**Answer- 1) Rs 130000**

Explanation-

Effective percent of interest earned = 7.7 + 7.7 + 7.7 × 7.7/100 = 15.9929%

Amount invested = 20790.77/15.9929 × 100 = Rs 130000Incorrect**Answer- 1) Rs 130000**

Explanation-

Effective percent of interest earned = 7.7 + 7.7 + 7.7 × 7.7/100 = 15.9929%

Amount invested = 20790.77/15.9929 × 100 = Rs 130000 - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude

**An amount of more than Rs 50000 and less than Rs 1 lakh was invested in company D for 1 year. In one year it became more than Rs 1 lakh. It was then invested in company E for two years at simple interest. After three years it amounts to Rs 116323.2. What was the amount invested initially?**Correct**Answer- 3) Rs 96000**

Explanation-

Let the amount invested is Rs x.

Amount after 1 year = x + 5% of x = 1.05x

Amount after further two years = 1.05x + (2 × 7.7)% of 1.05x = 1.05x + 0.1617x = 1.2117x

According to question,

1.2117x = 116323.2

x = 116323.2/1.2117 = Rs 96000Incorrect**Answer- 3) Rs 96000**

Explanation-

Let the amount invested is Rs x.

Amount after 1 year = x + 5% of x = 1.05x

Amount after further two years = 1.05x + (2 × 7.7)% of 1.05x = 1.05x + 0.1617x = 1.2117x

According to question,

1.2117x = 116323.2

x = 116323.2/1.2117 = Rs 96000 - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10). Robin travels across the country in the car for five days starting from Monday. He travels only in the day. He covers a total distance of 1800 km in these days. The following pie chart gives information about the distance travelled on each day in percentage. Read it carefully and answer the given questions.**

**The average speed of the car on Wednesday was 60 km/h. For how many hours did Robin takes rest on Wednesday (assuming that a day has 8 working hours)?**Correct**Answer- 2) 3.5 hours**

Explanation-

Distance travelled by Robin on Wednesday = 15% of 1800 = 270 km

Time for which Robin travelled on Wednesday = 270/60 = 4.5 hours

Time for which Robin takes rest = 8 – 4.5 = 3.5 hoursIncorrect**Answer- 2) 3.5 hours**

Explanation-

Distance travelled by Robin on Wednesday = 15% of 1800 = 270 km

Time for which Robin travelled on Wednesday = 270/60 = 4.5 hours

Time for which Robin takes rest = 8 – 4.5 = 3.5 hours - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10). Robin travels across the country in the car for five days starting from Monday. He travels only in the day. He covers a total distance of 1800 km in these days. The following pie chart gives information about the distance travelled on each day in percentage. Read it carefully and answer the given questions.**

**On Monday, a truck starts from the same place where Robin is supposed to reach at which Robin is supposed to reach on that day. It moves towards Robin at the speed of 24 km/h at the same time when Robin starts his journey. What is the speed of Robin’s car for the day if they met after 4 hours?**Correct**Answer- 5) 84 km/h**

Explanation-

Distance travelled by Robin on Monday = 24% of 1800 = 432 km

Let the speed of Robin’s car on Monday is x km/h

According to question, we have,

432/ (24 + x) = 4

432 = 96 + 4x

4x = 432 – 96 = 336

x = 336/4 = 84 km/hIncorrect**Answer- 5) 84 km/h**

Explanation-

Distance travelled by Robin on Monday = 24% of 1800 = 432 km

Let the speed of Robin’s car on Monday is x km/h

According to question, we have,

432/ (24 + x) = 4

432 = 96 + 4x

4x = 432 – 96 = 336

x = 336/4 = 84 km/h - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10). Robin travels across the country in the car for five days starting from Monday. He travels only in the day. He covers a total distance of 1800 km in these days. The following pie chart gives information about the distance travelled on each day in percentage. Read it carefully and answer the given questions.**

**On Tuesday, Robin travels 40% of the distance in x hours and remaining distance in 3x/2 hours. What is the value of x if the average speed of the car for the day is 80 km/h?**Correct**Answer- 1) 1.71**

Explanation-

Distance travelled on Tuesday = 19% of 1800 = 342 km

Total time taken = x + 3x/2 = 5x/2 hours

According to question, we have,

342/5x/2 = 80

684/5x = 80

5x = 8.55

x = 8.55/5 = 1.71Incorrect**Answer- 1) 1.71**

Explanation-

Distance travelled on Tuesday = 19% of 1800 = 342 km

Total time taken = x + 3x/2 = 5x/2 hours

According to question, we have,

342/5x/2 = 80

684/5x = 80

5x = 8.55

x = 8.55/5 = 1.71 - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude

**On Friday, Robin drives the car at the speed of 63 km/h. However, he stops in between for a nap due to which his average speed comes down to 45 km/h. For how much time does he stop?**Correct**Answer- 5) 96 min**

Explanation-

Distance travelled by Robin on Friday = 14% of 1800 = 252 km

Time he takes without stopping = 252/63 = 4 hours

Time he takes with stoppage = 252/45 = 5.6 hours

Time for which he stops = 5.6 – 4 = 1.6 hours = 96 minIncorrect**Answer- 5) 96 min**

Explanation-

Distance travelled by Robin on Friday = 14% of 1800 = 252 km

Time he takes without stopping = 252/63 = 4 hours

Time he takes with stoppage = 252/45 = 5.6 hours

Time for which he stops = 5.6 – 4 = 1.6 hours = 96 min - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude

**On Thursday, Robin drives car at the speed of 84 km/h. For what percent of the working hours he drives assuming that there are 10 working hours in a day?**Correct**Answer- 3) 60%**

Explanation-

Distance travelled on Thursday = 28% of 1800 = 504 km

Time taken = 504/84 = 6 hours

Required percentage = 6/10 × 100 = 60%Incorrect**Answer- 3) 60%**

Explanation-

Distance travelled on Thursday = 28% of 1800 = 504 km

Time taken = 504/84 = 6 hours

Required percentage = 6/10 × 100 = 60%

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