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Question 1 of 10
1. Question
1 pointsCategory: Quantitative Aptitude44.9% of 869.8 + 67.02% of 1249.8 – 21.03% of 540.04 = ?
Correct
Answer – 2) 1115
Explanation :
391+837-113 =1115Incorrect
Answer – 2) 1115
Explanation :
391+837-113 =1115 -
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeFind out the wrong number in the series given below
64, 66, 75, 103, 168, 295Correct
Answer – 4) 295
Explanation :
64 + (1³ + 1) = 66
66 + (2³ + 1) = 75
75 + (3³ + 1) = 103
103 + (4³ + 1) = 168
168 + (5³ + 1) = 294Incorrect
Answer – 4) 295
Explanation :
64 + (1³ + 1) = 66
66 + (2³ + 1) = 75
75 + (3³ + 1) = 103
103 + (4³ + 1) = 168
168 + (5³ + 1) = 294 -
Question 3 of 10
3. Question
1 pointsCategory: Quantitative Aptitudex² – 17x + 72 = 0
y² – 20y + 99 = 0
Correct
Answer – 4) X ≤ Y
Explanation:
x² – 17x + 72 = 0
x = 9, 8
y² – 20y + 99 = 0
y = 11, 9Incorrect
Answer – 4) X ≤ Y
Explanation:
x² – 17x + 72 = 0
x = 9, 8
y² – 20y + 99 = 0
y = 11, 9 -
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeSuresh sells 3 different books, first at profit 20%, second at 25% loss and third at 10% loss. During the whole transaction he bears the loss of Rs.120, find the cost price of first book if their SP is same?
Correct
Answer – 3) Rs. 360
Explanation:
x =A*120/100 = 1.2A
x=B*75/100 = 0.75B
x = C*90/100 = 0.9C
Loss = (A+B+C) – (1.2A+0.75B+0.9C) = 120
0.4A+ 0.4A/3 -0.2A =120
A =360Incorrect
Answer – 3) Rs. 360
Explanation:
x =A*120/100 = 1.2A
x=B*75/100 = 0.75B
x = C*90/100 = 0.9C
Loss = (A+B+C) – (1.2A+0.75B+0.9C) = 120
0.4A+ 0.4A/3 -0.2A =120
A =360 -
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeAjay and Bharat are partners in a business. They invest in the ratio 6:7, at the end of 9 months Bharat withdraws. If they receive profits at the end of year in the ratio of 2:3, find how long Ajay’s investment was used?
Correct
Answer – 3) 7 months
Explanation:
6*x : 9*7 = 2:3
x =7 monthsIncorrect
Answer – 3) 7 months
Explanation:
6*x : 9*7 = 2:3
x =7 months -
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeA rectangular tank 50 cm long and 40 cm wide contains water to a depth of 10 cm. a metal cube of side 20 cm placed in the tank so that one face of cube rests at the bottom of the tank. Find how many litre of water must be poured into the tank so as to just cover the cube?
Correct
Answer – 2) 12 litre
Explanation:
50*40*10 – 20^3 = 12,000cm ^3 = 12 litreIncorrect
Answer – 2) 12 litre
Explanation:
50*40*10 – 20^3 = 12,000cm ^3 = 12 litre -
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeSharmi is a very expert in bargaining. Once she went to a nearby shop. When Sharmi asked the price of watch the shopkeeper told her the price by increasing 18% of the original cost. But Sharmi insisted to decrease the price by 18% so the shopkeeper sold it by decreasing the price by 18% what is the loss or profit of shopkeeper and by how much percent?
Correct
Answer – 3) 3.24%
Explanation:
Loss = x^2/100 = 18^2/100 = 3.24%
10. 450 man-days of work can be
Actual price be Rs. 100
Increased price = 118
Sharmi price = 118*82/100 = 96.76 Loss = 100-96.76 = 3.24%Incorrect
Answer – 3) 3.24%
Explanation:
Loss = x^2/100 = 18^2/100 = 3.24%
10. 450 man-days of work can be
Actual price be Rs. 100
Increased price = 118
Sharmi price = 118*82/100 = 96.76 Loss = 100-96.76 = 3.24% -
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeSuresh can row 30 kmph in still water and he finds that it takes him twice as much time to row up than as to row down the same distance in the river. The speed of current in kmph?
Correct
Answer – 3) 10
Explanation:
1/30-R = 2/30+R
R =10Incorrect
Answer – 3) 10
Explanation:
1/30-R = 2/30+R
R =10 -
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeJyoti can do a piece of work in 18 days and Supriya can do the same work in 18 days. They started the work. After 3 days Reshma joined them, who can complete alone the same whole work in 3 days. What is the total number of days in which they had completed the work?
Correct
Answer – 2) 4 days
Explanation:
3(1/18+1/9)+ x(1/18+1/9+1/3) =1
x =1
total =3+1 = 4Incorrect
Answer – 2) 4 days
Explanation:
3(1/18+1/9)+ x(1/18+1/9+1/3) =1
x =1
total =3+1 = 4 -
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudePipe M basically used as inlet pipe and pipe N is used as outlet pipe. Pipe M and N both are opened simultaneously, all the time. When pipe M fills the tank and N empty the tank, it will take thrice the time than when both the pipe fill the tank. When pipe N is used for filling the tank, its efficiency remains constant. What is the ratio of efficiency of pipe M and pipe N respectively?
Correct
Answer – 1) 2:1
Explanation:
3(1/m-1/n) = (1/m+1/n)
m:n =2:1Incorrect
Answer – 1) 2:1
Explanation:
3(1/m-1/n) = (1/m+1/n)
m:n =2:1
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