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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Study the following graph given below and answer the questions given below.

In which of the following year was the amount of profit maximum?

Correct

Answer –5) None of these Explanation
For the year 1993, expenditure
= Income/ 100 + profit% x 100
=120/(100+7.5) x 100 = 111.63
Profit = Income – expenditure = 120 – 111.63
=8.37 lakh
Similarly
For the year 1994 profit = 20.86 lakh
For the year 1995 profit = 23.87 lakh
For the year 1996 profit = 25.32 lakh
For the year 1997 profit = 31.67 lakh
For the year 1998 profit = 32.35 lakh
The amount of profit is maximum for the year 1998.

Incorrect

Answer –5) None of these Explanation
For the year 1993, expenditure
= Income/ 100 + profit% x 100
=120/(100+7.5) x 100 = 111.63
Profit = Income – expenditure = 120 – 111.63
=8.37 lakh
Similarly
For the year 1994 profit = 20.86 lakh
For the year 1995 profit = 23.87 lakh
For the year 1996 profit = 25.32 lakh
For the year 1997 profit = 31.67 lakh
For the year 1998 profit = 32.35 lakh
The amount of profit is maximum for the year 1998.

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Study the following graph given below and answer the questions given below.

Approximately what was the average expenditure of the given years?

Study the following graph given below and answer the questions given below.

In which of the following years was the increase/decrease in percent profit from the previous year was maximum?

Correct

Answer – 1) 1994
Explanation
For the year 1994, increase in profit percentage
=15-7.5/7.5 x 100 = 100%(maximum)
Similarly for the year 1995 = 50%
1996 =22.22%
1997 =14.28%
1998 = 37.5%

Incorrect

Answer – 1) 1994
Explanation
For the year 1994, increase in profit percentage
=15-7.5/7.5 x 100 = 100%(maximum)
Similarly for the year 1995 = 50%
1996 =22.22%
1997 =14.28%
1998 = 37.5%

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Study the following graph given below and answer the questions given below.

Approximately what was the expenditure in 1994?

Correct

Answer – 3) 140 lakh
Explanation
Expenditure in 1994 = 160 / 115 x 100
= 140 lakh (approx)

Incorrect

Answer – 3) 140 lakh
Explanation
Expenditure in 1994 = 160 / 115 x 100
= 140 lakh (approx)

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Find the missing number in the given series?
9, 31, 73, 141, ______

Identify the wrong number in the given series?
144, 215, 540, 1890, 8505, 46777.5, 304053.75

Correct

Answer – 1) 215
Explanation
144 x 1.5 = 216
216 x 2.5 = 540
540 x 3.5 = 1890
1890 x 4.5 = 8505
And so on

Incorrect

Answer – 1) 215
Explanation
144 x 1.5 = 216
216 x 2.5 = 540
540 x 3.5 = 1890
1890 x 4.5 = 8505
And so on

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

A, B and C started a business with their investments in the ratio 1:2:4. After 6 month A invested the half amount more as before and B invested same the amount as before while C withdrew 1/4th of their investments. Find the ratio of their profits at the end of the year?

Correct

Answer 3) 5:12:14
Explanation

Incorrect

Answer 3) 5:12:14
Explanation

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

In measuring the sides of a rectangle, there is an excess of 5% on one side and 2% deficit on the other. What is the error percent in the area?

Correct

Answer – 5) 2.9%
Explanation

Incorrect

Answer – 5) 2.9%
Explanation

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

A train 150m long passes a Km stone in 30 seconds and another train of the same length travelling in opposite direction in 10 seconds. Find the speed of the second train?

Correct

Answer – 1) 90 Km/hr
Explanation
The length of first train= 150 meter
Length of second train= 150 meter
Speed of first train= 150 m/ 30 s= 5m/s
Speed of second train= S_{2}
Case 2
10 = (150 + 150)/ (S_{2} + 5)
10= 300/ (S_{2} + 5)
1= 30/ (S_{2} + 5)
S_{2}= 25 m/s
Speed of second train= 25 m/s
= 25 * (18/5) Km/hr
= 90 Km/hr

Incorrect

Answer – 1) 90 Km/hr
Explanation
The length of first train= 150 meter
Length of second train= 150 meter
Speed of first train= 150 m/ 30 s= 5m/s
Speed of second train= S_{2}
Case 2
10 = (150 + 150)/ (S_{2} + 5)
10= 300/ (S_{2} + 5)
1= 30/ (S_{2} + 5)
S_{2}= 25 m/s
Speed of second train= 25 m/s
= 25 * (18/5) Km/hr
= 90 Km/hr

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

Twelve applications apply for a job of which 5 are women and 7 are men. It is desired to select 3 persons for the job. What is the probability that at least one of the selected people is a woman?

Correct

Answer – 5) 37/44
Explanation
Total number of ways in which 3 persons can be selected out of 12 persons= ^{12}C_{3}
Number of ways at least one women= (^{5}C_{1} X ^{7}C_{2}) + (^{5}C_{2} X ^{7}C_{1}) + ^{5}C_{3}
= 105 + 70 + 10
= 185
Total number of outcomes= ^{12}C_{3}
=220
Probability= 185/220
= 37/44

Incorrect

Answer – 5) 37/44
Explanation
Total number of ways in which 3 persons can be selected out of 12 persons= ^{12}C_{3}
Number of ways at least one women= (^{5}C_{1} X ^{7}C_{2}) + (^{5}C_{2} X ^{7}C_{1}) + ^{5}C_{3}
= 105 + 70 + 10
= 185
Total number of outcomes= ^{12}C_{3}
=220
Probability= 185/220
= 37/44

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