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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

The total distance between two destinations is ‘x’ km. If the distance travelled along the stream is thrice of the total distance and the distance travelled against the stream is double of the total distance. If the time taken to cover the distance along the stream is 40% less than the time taken to cover the distance against the stream. If Sundar covers a distance of 21 km in 1 hour 24 minutes along the stream, then find the stream speed?

A sum of money is invested in Fund A at 7.5% per annum for SI. After 4 years an amount is received and that amount is invested in Fund B at 20% per annum for CI. If the interest received at the end of 2 years is 1430, find the initial invested amount?

Correct

Answer – 2) 2500
Explanation:
P[(1 + 20/100)^2 – 1] = 1430
P = 130 * 25 = Amount of Fund A
P[RT/100 + 1] = 130 * 25
P[30/100 + 1] = 130 * 25
P = 2500

Incorrect

Answer – 2) 2500
Explanation:
P[(1 + 20/100)^2 – 1] = 1430
P = 130 * 25 = Amount of Fund A
P[RT/100 + 1] = 130 * 25
P[30/100 + 1] = 130 * 25
P = 2500

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Devi’s present age is three times his son’s present age and nine-thirteenth of his father’s present age. The sum of their ages after five years is 115 years. What is the sum of the present ages of Devi’s son and Devi’s father?

Correct

Answer – 2) 64
Explanation:
Present age of F+S+D = 115-15 = 100
S = F/3; D = 13F/9
F (1+1/3+13/9) = 100
F =36; S = 12; D =52
D+S = 52+12 = 64

Incorrect

Answer – 2) 64
Explanation:
Present age of F+S+D = 115-15 = 100
S = F/3; D = 13F/9
F (1+1/3+13/9) = 100
F =36; S = 12; D =52
D+S = 52+12 = 64

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Find out the wrong number in the series given below
10, 12, 22, 50, 132, 409

Directions.Q(7 – 10) Study the given table carefully and answer the following questions

Total Strength = Seminar Participants + Conference Participants + Who didn’t participate in any event

What is the average of number of Conference Participants participated from Colleges M, O and P.

Correct

Answer – 5) 670
Explanation:
Total strength in M = 800+35M/100 + 370; M = 1800; Conference Participants = 630
Total strength in O = 680+30O/100 + 545; O = 1750; Conference Participants = 525
Total strength in P = 850+45P/100 + 195; P = 1900; Conference Participants = 855
Average = (630+525+855)/3 = 670

Incorrect

Answer – 5) 670
Explanation:
Total strength in M = 800+35M/100 + 370; M = 1800; Conference Participants = 630
Total strength in O = 680+30O/100 + 545; O = 1750; Conference Participants = 525
Total strength in P = 850+45P/100 + 195; P = 1900; Conference Participants = 855
Average = (630+525+855)/3 = 670

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

Directions.Q(7 – 10) Study the given table carefully and answer the following questions

Total Strength = Seminar Participants + Conference Participants + Who didn’t participate in any event

If all females and 110 males in College Q didn’t participate in the any event, then total how many males have participated in the any event?

Correct

Answer – 2) 1590
Explanation:
In College Q total strength:
x = 790+40x/100+ 410
x =2000
Conference Participants = 800
Total male Participants = 790+800 =1590

Incorrect

Answer – 2) 1590
Explanation:
In College Q total strength:
x = 790+40x/100+ 410
x =2000
Conference Participants = 800
Total male Participants = 790+800 =1590

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

Directions.Q(7 – 10) Study the given table carefully and answer the following questions

Total Strength = Seminar Participants + Conference Participants + Who didn’t participate in any event

What is the average of total strength in all five Colleges together?

Directions.Q(7 – 10) Study the given table carefully and answer the following questions

Total Strength = Seminar Participants + Conference Participants + Who didn’t participate in any event

Approximately total number of students who didn’t participate in any event in all Colleges together forms what percent of the total strength in all Colleges together?

Correct

Answer – 1) 21%
Explanation:
Total strength who didn’t participate in any event = 370+480+545+195+410 = 2000
Total strength in all Colleges = 9450
% = 2000/9450*100 = 21%

Incorrect

Answer – 1) 21%
Explanation:
Total strength who didn’t participate in any event = 370+480+545+195+410 = 2000
Total strength in all Colleges = 9450
% = 2000/9450*100 = 21%

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