Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions in Quadratic Equations which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!
You have to solve equation I and II ,Give answer
1)If X>Y
2)If X<Y
3)If X≥ Y
4)If X≤ Y
5)If X=Y or cannot be established
- I. X2 – 3X + 2= 0
II. 9Y2 – 9Y + 2 = 0
Answer
Answer – 1)If X>Y
Explanation :
(x-1)(x-2) = 0
X=1,2
(3y-1)(3y-2) = 0
Y =1/2,1/3
1,2,1/2,1/3
Xxyy => x>y
- I. X2 – 6X + 8= 0
II.Y2 – 8Y + 15 = 0
Answer
Answer – 5)If X=Y or cannot be established
Explanation :
(x-4)(x-2) = 0
X=4,2
(y-5)(y-3) = 0
Y=5,3
5,4,3,2 = yxyx
- I. 2X2 – 3X – 2= 0
II. 6Y2 + 7Y + 2 = 0
Answer
Answer – 3)If X≥ Y
Explanation :
(x-2)(2x+1) = 0
X=2,-1/2
(3x+2)(2x+1) = 0
X=-2/3,-1/2
2,-0.5,-0.5, -0.6
Xxyy => X≥ Y
- I. 2X2 + 7X + 6= 0
II. 2Y2 + Y – 3 = 0
Answer
Answer – 4)If X≤ Y
Explanation :
(x+2)(2x+3) = 0
X= -2,-3/2
(2y+3)(y-1) = 0
Y=1,-3/2
1,-3/2,-3/2,-2
yyxx => X≤ Y
- I. 6X2 + 11X + 3= 0
II. 3Y2 – 2Y – 1 = 0
Answer
Answer – 4)If X≤ Y
Explanation :
(3x+1)(2x+3) = 0
X= -1/3, -3/2
(y-1)(3y+1) = 0
Y = 1,-1/3
1,-1/3,-1/3,-3/2
Yyxx => X≤ Y
- I. 5X2 – 126X + 25= 0
II. 9Y2 – 22Y + 8 = 0
Answer
Answer – 5)If X=Y or cannot be established
Explanation :
(5x-1)(x-25) = 0
X=1/5, 25
(y-2)(9y-4) = 0
Y = 2,4/9
25,2,4/9,1/5
Xyyx
- I. 2X2 – 9X + 7= 0
II. 6Y2 + 7Y – 10 = 0
Answer
Answer – 1)If X>Y
Explanation :
(2x-7)(x-1) = 0
X=7/2,1
(y+2)(6y-5) = 0
y= -2, 5/6
7/2,1,5/6, -2
Xxyy = x>y
- I. X + 1/x = 10/3
II. 4-11y = 3y2
Answer
Answer – 3)If X≥ Y
Explanation :
(3x-1)(x-3) = 0
X=3,1/3
(3y-1)(y+4) = 0
Y = 1/3,-4
3,1/3,1/3, -4
Xxyy = > X≥ Y
- I. X= (1024)1/2
II. Y2 = 1024
Answer
Answer – 3)If X≥ Y
Explanation :
X = 32
Y=±32
x≥y
- I. X2 – 20X = -91
II. 3Y2 = 22Y – 32
Answer
Answer – 1)If X>Y
Explanation :
(x-7)(x-13) = 0
X=7,13
(3x-16)(x-2) = 0
X=2,16/3
7,13,16/3,2
Xxyy = x>y
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