Aptitude Questions: Quadratic Equations Set 13

Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions in Quadratic Equations which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

Follow the link To solve Quadratic Equations with the help of Number Line

You have to solve equation I and II ,Give answer
A) If X > Y
B) If X < Y
C) If X ≥ Y
D) If X ≤ Y
E) If X = Y or cannot be established

1. I. 2X² + 11X + 12= 0
   II.5Y² + 27Y + 10 = 0
   

   Answer & Explanation

   Answer – 5)If X=Y or cannot be established
   Explanation :
   (2x+3)(x+4) = 0
   X= -3/2, -4
   (5y+2)(y+5) = 0
   Y = -5, -2/5
   -0.4, -1.5, -4, -5 => yxxy
   
   
   
2. I. 25X² + 25X + 6= 0
   II.5Y² +  20Y + 20 = 0
   

   Answer & Explanation

   Answer – 1)If X>Y
   Explanation :
   (5x+2)(5x+3) = 0
   X = -2/5, -3/5
   (5y+10)(y+2) = 0
   Y = -2, -10/5 = -2, -2
   -2/5, -3/5, -2, -2=> xxyy
   x>y
   
   
   
3. I. 3X² + 7X + 4= 0
   II.3Y² +  10Y + 8 = 0
   

   Answer & Explanation

   Answer – 3)If X≥ Y
   Explanation :
   (x+1)(3x+4) = 0
   X=-1, -4/3
   (3y+4)(y+2) =0
   Y = -4/3, -2
   -1, -4/3, -4/3, -2 => xxyy
   X≥ Y
   
   
   
4. I.(x+y)² = 900
   II.Y + 1689 = 1705
   

   Answer & Explanation

   Answer – 2)If X<Y
   Explanation :
   y = 1705 – 1689 = 16
   (x + y)² = 900
   x + y = 30
   x = 30 – 16 = 14
   16>14
   Clearly, x < y
   
   
   
5. I.8X² + 3X – 38= 0
   II.6Y² –  29Y + 34 = 0
   

   Answer & Explanation

   Answer – 4)If X≤ Y
   Explanation :
   8X² + 3X – 38= 0
   (8x + 19) (x – 2) = 0
   x = 2 or -19/8
   6Y² –  29Y + 34 = 0
   (y – 2) (6y – 17) = 0
   y = 2 or 17/6
   17/6, 2, 2, -19/8 => yyxx
   X≤ Y
   
   
   
6. 9x – 3x = 64.55 + 19.45
   √(y *155) = 7 + 6
   

   Answer & Explanation

   Answer – 5)If X=Y or cannot be established
   Explanation :
   9x – 3x = 64.55 + 19.45
   6x = 84
   x = 14
   √(y *155) = 7 + 6 =13
   y + 155 = 169
   y = 169 – 155 = 14
   x=y
   
   
   
7. I.2X² + 19X + 44= 0
   II.2Y² +  3Y – 20 = 0
   

   Answer & Explanation

   Answer – 4)If X≤ Y
   Explanation :
   2X² + 19X + 44= 0
   (x + 4) (2x + 11) = 0
   x = -4 or -11/2
   2Y² +  3Y – 20 = 0
   (y + 4) (2y – 5) = 0
   y = -4 or 5/2
   5/2, -4,-4,-5/2 = yyxx
   X≤ Y
   
   
   
8. I.P² + 9P = 2P – 12
   II.4Q² +  8Q = 4Q + 8
   

   Answer & Explanation

   Answer – 2)If X<Y
   Explanation :
   p² + 9p = 2p – 12
   (p + 3) (p + 4 ) = 0
   p = – 3, – 4
   4q² + 8q = 4q + 8
   4q2 + 4q – 8 = 0
   (q + 2) (q – 1) = 0
   q = -2, 1
   1, -2,-3,-4 => QQPP
   P<Q
   
   
   
9. I.2X² – 7X + 6= 0
   II.4Y² = 9
   

   Answer & Explanation

   Answer – 3)If X≥ Y
   Explanation :
   2X² – 7X + 6= 0
   (x – 2) (2x – 3) = 0
   x = 2 or x =3/2
   4Y² = 9
   Y = ±3/2 = 3/2, -3/2
   2,3/2,3/2,-3/2 = xxyy
   x≥y
   
   
   
10. I. X²  = 1296
    II.Y  = √1296
    

    Answer & Explanation

    Answer – 4)If X≤ Y
    Explanation :
    X = ±36
    Y = 36
    X≤Y
    
    
    

Note : Dear Aspirants try to post your attempts and time here