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Quantitative Aptitude Questions for IBPS/RRB Exam Set- 3

Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From all topics , which are Important for upcoming IBPS and RRB exams. We have included Some questions that are repeatedly asked in exams !!

There are two companies Company A and company B.Both companies have four different types of department,viz Web Development, Software Development ,Networking and Testing.In Company X there are total 7000 employees.Company B has thirty percent more employees that of Company A.Twenty percent employees of Company A are in Web Development.One-fourth of the total number of employees of Company A are in Testing. Twentythree precent of the employees of company A are in Software developement.Remaining employees of Company A are in Networking.The total number of employees in Testing in both companies together is 4800.Thirty percent of the number of employees of Company B are in Software Development.Ten percent of total employees of Company B are in Networking.The remaining are in web development.

  1. What is the ratio of employees in the department of Networking of company A to the number of employees in software development of Company B?
    A. 13:7
    B. 7:13
    C. 32:39
    D. Data Inadequate
    E. None of these
    Answer
    C.
                                           Company A    Company B
    Web development-                  1400         2410
    Software Development-           1610         2730
    Networking-                            2240         910
    Testing-                                  1750         3050

  2. What is the total number of employees in Web Development of Company A and Testing of Company B together?
    A. 4490
    B. 4590
    C. 4350
    D. 4450
    E. 4200
    Answer
    D.
                                           Company A    Company B
    Web development-                  1400         2410
    Software Development-           1610         2730
    Networking-                            2240         910
    Testing-                                  1750         3050

  3. What is the difference between the number of employees in Testing of Company A and the total number of employees in Software Development and Networking together of company B?
    A. 1990
    B. 1780
    C. 1870
    D. 1790
    E. None of these
    Answer
    E.
                                           Company A    Company B
    Web development-                  1400         2410
    Software Development-           1610         2730
    Networking-                            2240         910
    Testing-                                  1750         3050

  4. The total number of employees of Web Development of both companies together is approximately what percentage of total number of employees in Company B?
    A. 35
    B. 42
    C. 46
    D. 38
    E. 31
    Answer
    B.
                                           Company A    Company B
    Web development-                  1400         2410
    Software Development-           1610         2730
    Networking-                            2240         910
    Testing-                                  1750         3050

  5. If there a party is organised and entry fees for Networking dept is 45 ,what will be the total amount(in Rs.) paid by the department of Company A?
    A. 100800
    B. 108000
    C. 100800
    D. 10800
    E. 18000
    Answer
    C.
                                           Company A    Company B
    Web development-                  1400         2410
    Software Development-           1610         2730
    Networking-                            2240         910
    Testing-                                  1750         3050

  6. Sita,Gita and meeta participated in race competion in a circular track.They complete one round in 24,18 and 20 seconds respectively.In how many minutes will all three meet again at the starting point?
    A. 8
    B. 5
    C. 6
    D. 2
    E. 3
    Answer
    C.
    LCM of 24,18 and 20 is 360.So
    360seconds=6minutes

  7. A person invested a certain amount in share A and share B in the ratio 3:5.At the end of one year ,he earned total 60% on the amount he invested. After some time he decided to invest the total amount got at the end of the year in the ratio 9:7 in share A and share B.If the amount of reinvestment in share B was 266140,what was the original amount invested for share A?
    A. 42,575
    B. 141,757
    C. 124,575
    D. 124,757
    E. 142,575
    Answer
    E.
    Reinvested amount in share B=2661400
    Total amount reinvested= 266140x(16/7)
    =608320
    Total amount invested before=608320/1.6
    =380200
    Original amount invested in
    shareA=380200x(3/8)=142575

  8. X can do a work in 20 days. Y can do the half of the work  in 12 days. Z can do 1/3rd of the work  in 5 days.They were assigned to a task.All started together but X leaves the task 2days before completion and Z leaves the work 4 days before completion.Y is the only person to work untill task is finished.What is the total time(approximately) taken to complete the task?
    A. 7.5 days
    B. 8.5 days
    C. 6days
    D. 10days
    E. None of these
    Answer
    B.
    X one day work-20days
    Y one day work-12×2=24days
    Z one day work-5×3=15days
    Lets the work finished in d Days.So
    (d-2)/20 + d/24 + (d-4)/15 = 1
    =>d=8.6(approx 8.5)

  9. If x and y are integers ,is x+y an odd number?
    i. x≤y ii. 23<x≤25 iii. 24<y≤26
    A. Only i and ii together are sufficient
    B. Any two of three are sufficient
    C. Only i and iii together are sufficient
    D. only ii and iii together are sufficient
    E. All i,ii and iii are together not sufficient-
    Answer
    E.
    from (ii) x=24,25
    (iii) y=25,26
    Considering all statements
    x=24,25 and y=25
    Still when x=24,x+y=24+25=49(0dd no)
    x=24,x=y=24+24=48(even no)

  10. Find the wrong number according to the series
    198,150,110.72,42,18
    A. 18
    B. 150
    C. 72
    D. 110
    E. 42
    Answer
    D.
    Here number are arranged as -6×8 , -6×7 and so on..





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