Current Affairs APP

Quantitative Aptitude Questions for IBPS/RRB Exam Set – 25

Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From all topics , which are Important for upcoming IBPS and RRB exams. We have included Some questions that are repeatedly asked in exams.

1-5: An urn contains 4 green, 5 blue, 2 red and 3 yellow marbles.

  1. If two marbles are drawn at random, what is the probability that both are red or at least one is red?
    1) 25/91
    2) 1/7
    3) 199/364
    4) 133/191
    Answer
    1) 25/91
    Explanation:
    2C2 + (2C1 * 12C1) / 14C2

  2. If three marbles are drawn at random, what is the probability that at least one is yellow?
    1) 1/3
    2) 199/364
    3) 165/364
    4) 3/11
    Answer
    2) 199/364
    Explanation:
    At least one marble is yellow. That means one yellow marble or two yellow marbles or three yellow marbles.
    1 – (11C3/14C3)

  3. If eight marbles are drawn at random, what is the probability that there are equal numbers of marbles of each colour?
    1) 4/7
    2) 361/728
    3) 60/1001
    4) 1/1
    Answer
    3) 60/1001
    Explanation:
    4C2 * 5C2 * 2C2 * 3C2 / 14C8

  4. If three marbles are drawn at random, what is the probability that none is green?
    1) 2/7
    2) 253/728
    3) 10/21
    4) 30/91
    Answer
    4) 30/91
    Explanation:
    10C3/14C3

  5. If four marbles are drawn at random, what is the probability that two are blue and two are red?
    1) 10/1001
    2) 9/14
    3) 17/364
    4) 2/7
    5) None of these
    Answer
    1) 10/1001
    Explanation:
    5C2 * 2C2 / 14C4

  6. Seema bought 20 pens, 8 packets of wax colours, 6 calculators and 7 pencil boxes, The price of one pen is Rs. 7, one packet of wax colour is for Rs. 22, one calculator is for Rs. 175 and one pencil box costs Rs. 14 more than the combined price of one pen and one packet of wax colours. How much amount did Seema pay to the shopkeeper?
    1) Rs. 491
    2) Rs. 1, 725
    3) Rs. 1, 667
    4) Rs. 1, 527
    Answer
    3) Rs. 1, 667

  7. An HR Company employs 4800 persons, out of which 45 percent are males and 60 percent of the males are either 25 years or older. How many males are employed in that HR Company who are younger than 25 years?
    1) 2640
    2) 2160
    3) 1296
    4) 864
    Answer
    4) 864

  8. The ratio of the present age of Manisha and Deepali is 5 : X. Manisha is 9 years younger than Parineeta. Parineeta’s age after 9 years will be 33 years. The difference between Deepali’s and Manisha’s age is the same as the present age of Parineeta. What should come in place of X?
    1) 23
    2) 39
    3) 13
    4) Cannot be determined
    Answer
    3) 13
    Explanation:
    Parineeta’s present age = 24 yrs.
    Manisha’s present age = 15 yrs (24 – 9)
    Deepali’s present age = 15 + 24 = 39 yrs.
    Ratio of the present age of Manisha and Deepali = 15 : 39 = 5 : 13
    x = 13

  9. In an examination, 30% of the total students failed in Hindi, 45% failed in English and 20% failed in both the subjects. Find the percentage of those who passed in both the subjects.
    1) 35.7%
    2) 35%
    3) 40%
    4) 45%
    Answer
    4) 45%
    Explanation:
    Let the number of students be 100. Number of students who failed in Hindi is 30%, n(H) = 30
    Number of students who failed in English is 45%, n(E) = 45
    Number of students who failed in both the subjects is 20% , n(H and E) = 20
    Applying the rule,
    n(H and E) = n(H) + n(E) – n(H or E) = 30 + 45 – 20 = 55
    Percentage of students who failed in Hindi or English or both the subjects = 55%
    Number of students who passed in both the subjects = 100 – 55 = 45%

  10. Area of a rectangle is equal to the area of the circle whose radius is 21 cms. If the length and the breadth of the rectangle are in the ratio 14 : 11 respectively, what is its perimeter?
    1) 142 cm
    2) 140 cm
    3) 132 cm
    4) 150 cm
    Answer
    4) 150 cm
    Explanation:
    l * b = 22/7 * 21 * 21 = 1386
    l = 14x, b = 11x
    so, 14x * 11x = 1386
    solve, we get x = 3
    therefore, l = 14*3 = 42, b = 11*3 = 33
    perimeter = 2(42+33)





Exit mobile version