IBPS PO 2019 Prelims: Quant Test Day 12

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  1. Quantitative Aptitude 0%
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  1. Question 1 of 10
    1. Question
    1 points
    Category: Quantitative Aptitude

    2x2-7x+6 = 0
    3y2-8x+4 = 0

    Correct

    Answer: 3. x = y or relationship can’t be determined.
    Explanation:
    2x2-7x+6 = 0
    2x2-4x-3x+6 = 0
    2x(x-2)-3(x-2) =0
    x =2, 3/2

    3y2-8x+4 = 0
    3y2-6y-2y+4 = 0
    3y(y-2)-2(y-2) =0
    y = 2, 2/3

    Incorrect

    Answer: 3. x = y or relationship can’t be determined.
    Explanation:
    2x2-7x+6 = 0
    2x2-4x-3x+6 = 0
    2x(x-2)-3(x-2) =0
    x =2, 3/2

    3y2-8x+4 = 0
    3y2-6y-2y+4 = 0
    3y(y-2)-2(y-2) =0
    y = 2, 2/3

  2. Question 2 of 10
    2. Question
    1 points
    Category: Quantitative Aptitude

    x2 -8x+15=0
    y2+2y-15 = 0

    Correct

    Answer: 2. x ≥ y
    Explanation:
    x2 -8x+15=0
    x2 -5x-3x+15=0
    x(x-5)-3(x-5) = 0
    x =3, 5

    y2+2y-15 = 0
    y2+5y-3y-15 = 0
    y(y+5)-3(y+5)=0
    y = -5, 3

    Incorrect

    Answer: 2. x ≥ y
    Explanation:
    x2 -8x+15=0
    x2 -5x-3x+15=0
    x(x-5)-3(x-5) = 0
    x =3, 5

    y2+2y-15 = 0
    y2+5y-3y-15 = 0
    y(y+5)-3(y+5)=0
    y = -5, 3

  3. Question 3 of 10
    3. Question
    1 points
    Category: Quantitative Aptitude

    Adolf usually gains the cost price of 10m of cloth for every 40m sale of cloth. What is the percentage gain?

    Correct

    Answer – 1) 25 %
    Explanation

    Profit = 10m
    CP = 40 m
    10/40 x 100 = 25%

    Incorrect

    Answer – 1) 25 %
    Explanation

    Profit = 10m
    CP = 40 m
    10/40 x 100 = 25%

  4. Question 4 of 10
    4. Question
    1 points
    Category: Quantitative Aptitude

    A,B and C invest money in the ratio of 2:5:4 for the same period and the difference of C’s and A’s share of the profit is Rs.2400, what will be the profit amount to in 4 years if invested at the rate of 8% per annum SI?

    Correct

    Answer – 1) 17424
    Explanation

    Sum of the part of the ratio = 2 + 5 +4 = 11
    Profit = 2400 x 11/ (4-2) = Rs13200
    Amount = 13200 + 13200 x 4 x 8/100 = 17424

    Incorrect

    Answer – 1) 17424
    Explanation

    Sum of the part of the ratio = 2 + 5 +4 = 11
    Profit = 2400 x 11/ (4-2) = Rs13200
    Amount = 13200 + 13200 x 4 x 8/100 = 17424

  5. Question 5 of 10
    5. Question
    1 points
    Category: Quantitative Aptitude

    Upstream speed of boat A and B are in the ratio 2:3 respectively and their downstream speeds in the ratio 6:7 respectively. What is the ratio of
    their speeds in still water?

    Correct

    Answer – 1) 4:5
    Explanation

    Downstream speed of boat A = a+s
    Downstream speed of boat B = b+s
    Upstream speed of boat A = a-s
    Upstream speed of boat B = b-s
    Then
    (a-s):(b-s) = 2:3
    S= 3a-2b (1)
    And (a+s): (b+s) = 6:7
    S = 6b -7a (2)
    From 1 and 2
    A:B =4:5

    Incorrect

    Answer – 1) 4:5
    Explanation

    Downstream speed of boat A = a+s
    Downstream speed of boat B = b+s
    Upstream speed of boat A = a-s
    Upstream speed of boat B = b-s
    Then
    (a-s):(b-s) = 2:3
    S= 3a-2b (1)
    And (a+s): (b+s) = 6:7
    S = 6b -7a (2)
    From 1 and 2
    A:B =4:5

  6. Question 6 of 10
    6. Question
    1 points
    Category: Quantitative Aptitude

    Q (6-10) The following line graph shows the runs scored by two Indian batsmen Rohit and Shikhar in different years.

    Total runs scored by Shikhar in years 2016, 2017 and 2018 together are how much percent more than the total runs scored by Rohit in years 2014, 2015 and 2016 together?

    Correct

    Answer- 3) 8.6%
    Explanation-
    Total runs scored by Shikhar in 2016, 2017 and 2018 = 850 + 930 + 564 = 2344
    Total runs scored by Rohit in 2014, 2015 and 2016 = 875 + 548 + 735 = 2158
    Required percentage =( 2344 – 2158)/2158 × 100 = 18600/2158 = 8.6 %

    Incorrect

    Answer- 3) 8.6%
    Explanation-
    Total runs scored by Shikhar in 2016, 2017 and 2018 = 850 + 930 + 564 = 2344
    Total runs scored by Rohit in 2014, 2015 and 2016 = 875 + 548 + 735 = 2158
    Required percentage =( 2344 – 2158)/2158 × 100 = 18600/2158 = 8.6 %

  7. Question 7 of 10
    7. Question
    1 points
    Category: Quantitative Aptitude

    Q (6-10) The following line graph shows the runs scored by two Indian batsmen Rohit and Shikhar in different years.

    The difference between the average runs scored by Rohit and that by Shikhar in all the given years is:

    Correct

    Answer- 1) 114
    Explanation-
    Total runs scored by Rohit in the given years = 875 + 548 + 735 + 1057 + 1160 = 4375
    Total runs scored by Shikhar = 426 + 1035 + 850 + 930 + 564 = 3805
    Required difference = 4375/5 – 3805/5 = 875 – 761 = 114

    Incorrect

    Answer- 1) 114
    Explanation-
    Total runs scored by Rohit in the given years = 875 + 548 + 735 + 1057 + 1160 = 4375
    Total runs scored by Shikhar = 426 + 1035 + 850 + 930 + 564 = 3805
    Required difference = 4375/5 – 3805/5 = 875 – 761 = 114

  8. Question 8 of 10
    8. Question
    1 points
    Category: Quantitative Aptitude

    Q (6-10) The following line graph shows the runs scored by two Indian batsmen Rohit and Shikhar in different years.

    In year 2013, the runs scored by Rohit are 25% more than the average runs scored by him in year 2016, 2017 and 2018 and the runs scored by Shikhar are 50% more than the average runs scored by him in year 2014 and 2016. Find the difference between the runs scored by Rohit and by Shikhar in 2013.

    Correct

    Answer- 3) 273
    Explanation-
    Runs scored by Rohit in 2013 = 125% of (735 + 1057 + 1160)/3 = 1230
    Runs scored by Shikhar in 2013 = 150% of (426 + 850)/2 = 957
    Required difference = 1230 – 957 = 273

    Incorrect

    Answer- 3) 273
    Explanation-
    Runs scored by Rohit in 2013 = 125% of (735 + 1057 + 1160)/3 = 1230
    Runs scored by Shikhar in 2013 = 150% of (426 + 850)/2 = 957
    Required difference = 1230 – 957 = 273

  9. Question 9 of 10
    9. Question
    1 points
    Category: Quantitative Aptitude

    Q (6-10) The following line graph shows the runs scored by two Indian batsmen Rohit and Shikhar in different years.

    In 2018, Rohit played four more matches than Shikhar and his average runs per match were 25.5 more than that of Shikhar. How many matches did Shikhar play in year 2018 ?

    Correct

    Answer- 4) 12
    Explanation-
    Let the number of matches played by Shikhar in 2018 be x, then the number of matches played by Rohit in 2018 would be x + 4.
    According to question, we have, 1160/x+4 – 564/x = 25.5
    By solving, we have x = 12

    Incorrect

    Answer- 4) 12
    Explanation-
    Let the number of matches played by Shikhar in 2018 be x, then the number of matches played by Rohit in 2018 would be x + 4.
    According to question, we have, 1160/x+4 – 564/x = 25.5
    By solving, we have x = 12

  10. Question 10 of 10
    10. Question
    1 points
    Category: Quantitative Aptitude

    Q (6-10) The following line graph shows the runs scored by two Indian batsmen Rohit and Shikhar in different years.

    In which year, the difference between the runs scored by Rohit and by Shikhar is maximum?

    Correct

    Answer- 5) 2018
    Explanation-
    Apparently, the difference between the runs scored by Rohit and by Shikhar is maximum in 2018 (596).

    Incorrect

    Answer- 5) 2018
    Explanation-
    Apparently, the difference between the runs scored by Rohit and by Shikhar is maximum in 2018 (596).


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