Hello Aspirants.

Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample in **Profit and loss** , which is common for all the competitive exams. We have included Some questions that are repeatedly asked in exams!!!

**Bank PO Level Questions**

**A toy is sold for Rs.336, if the % of profit is equal to cost price, then find CP ?**

1.137

2.140

3.135

4.120

5.None of these

###### Answer & Explanation

Answer –**2.140**

**Explanation :**

(100+x)% of X = 336

100x+x^{2}= 33600

x^{2}+100x – 33600 = 0

(x+240x)(x-140x) =0

X = 140

**Shopkeeper purchased some goods for Rs.900 and sold one-third of the goods at a loss of what 12%, then at gain % should the remainder goods he sold to gain 18% profit on the whole transaction ?**

1.31%

2.26%

3.33%

4.18%

5.None of these

###### Answer & Explanation

Answer –**3.33%**

**Explanation :**

1/3^{rd}at 12% loss = 900/3 =300*88/100 =264

900*18/100 = 108 => 600+162+36 = 798

198/600 *100 = 33%

**A bought ‘X’ quantity of pencils for Rs.500 and he sold 2/5 part for 5% loss and at which percent he must sell his rest of the quantity so that he would gain overall 10% profit ?**

1.10%

2.20%

3.17%

4.15%

5.None of these

###### Answer & Explanation

Answer –**2.20%**

**Explanation :**

500*2/5 = 200

5%L = 200*95/100 = 190

500+10+(500*10/100) = 510+50 = 560

60/500 * 100 = 20%

**A dealer marked the price of an item 20% above cost price. He allowed two successive discounts of 10% and 25% to a customer. A a result he incurred a loss of Rs.684. At what price did he sell the item to the customer ?**

1.1670

2.2768

3.1817

4.2916

5.None of these

###### Answer & Explanation

Answer –**4.2916**

**Explanation :**

CP = 100

MP = 120

120*90/100 = 108; 108*75/100 = 81

Loss = 100 – 81 = 19%

CP = 100/19*684 = 3600

SP = 3600*81/100 = 2916

**A man gains 15% by selling an article for a certain price. If he sells it at double the price, then the % of profit will be**

1.130%

2.115%

3.30%

4.40%

5.None of these

###### Answer & Explanation

Answer –**1.130%**

**Explanation :**

CP = 100, 15% GAIN = 115

SP = 230

P = 230-100 = 130

% = 130%

**A man went to shop to buy mobile for Rs.3500, the rate of sales tax being 8%. He tell the shopkeeper to reduce the price of mobile to such an extent that has to pay Rs.3500, inclusive of all taxes. Find the reduction price.**

1.Rs.210

2.Rs.260

3.Rs.320

4.Rs.140

5.None of these

###### Answer & Explanation

Answer –**2.Rs.260**

**Explanation :**

3500*100/108 = 3240

3500-3240 = 260

**An item was bought at Rs. X and sold at Rs.Y, thereby earning a profit of 15%. Had the value of X been 15% less and the value of Y been Rs.52 less, a profit of 20% would have been earned, What was the value of X ?**

1.650

2.800

3.400

4.350

5.None of these

###### Answer & Explanation

Answer –**3.400**

**Explanation :**

x(1.15)=y———–1

x(0.85)(1.2)=y-52——————-2

Sub 1 in 2, and solve x

(1.15)x-(1.02)x=52

(0.13)x=52

x=400

**An article passing threw two hands, is sold at profit of 40 % at the original price , if the first dealer makes a profit of 15 % , then the profit made by second dealer.**

1.25%

2.26%

3.18%

4.22%

5.None of these

###### Answer & Explanation

Answer –**4.22%**

**Explanation :**

Total Profit = [P1 + P2 +(P1*P2/100)]

40 = 15 + P2 + (15*P2)

25-p2 = 15P2/100

2500 = 15p2+100p2

P2 = 2500/115 = 21.7% = 22%

**A boy sells a Radio to B at a 10 % loss, B sells it to C at 25 % gain and C sells it to D at a loss of 8 %, if D pays Rs 1625 for it then how much does A pay for.**

1.Rs.1620

2.Rs.1560

3.Rs.1570

4.Rs.1760

5.None of these

###### Answer & Explanation

Answer –**3.Rs.1570**

**Explanation :**

Cost price of A = 1625*[(100*100*100)/(90*125*92)] = 1570

**What is the maximum % discount that a man can offer on her MP so that he ends up selling at no profit or loss, if he had initially marked his goods up by 35% (approximately)?**

1.20%

2.32%

3.27%

4.30%

5.None of these

###### Answer & Explanation

Answer –**4.26%**

**Explanation :**

35-x-(35*x/100) = 0

3500/100 –(100x+35x/100) = 0

35 = 135/100

X = 35*100/135 = 25.9 = 26%

**Note:** Dear Readers if you have any doubt in any chapter in Quants you can ask here. We will clear your doubts and u can share your tricks here.

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