Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From DATA SUFFICIENCY topic, which are common for all the IBPS, SBI exams, RBI, SSC and other competitive exams. We have included some questions that are repeatedly asked in exams !!!
Directions (1-10):
(A) If the data in statement I alone is sufficient to answer the question.
(B) If the data in statement II alone is sufficient to answer the question.
(C) If the data either in statement I alone or statement II alone are sufficient to answer the question.
(D) If the data given in both I and II together are not sufficient to answer the question.
(E) If the data in both the statements I and II together are necessary to answer the question.
- What is the time that Kirti took to reach her destination?
I. Shweta took 45 minutes to reach the same destination.
II. The ratio between the speeds of Kirti and Shweta is 9 : 5.
Answer & Explanation
(E) If the data in both the statements I and II together are necessary to answer the question.
Explanation:
From II, speeds of Kirti and Shweta are 9x and 5x respectively.
From I, Shweta’s time = 45 minutes
Since distance is same, from both statements:
So 5x*45 = 9x* Kirti’s time
So Kirti’s time = 25 minutes.
- A man borrowed a total sum of Rs 24000 from two moneylenders. For one loan, he paid interest at 6 % p.a. and for the other 4% p.a. How much money did he borrow at each rate?
I. The sum of interests after 1 year was Rs 5434
II. The interest on one sum was twice that on the other.
Answer & Explanation
(C) If the data either in statement I alone or statement II alone are sufficient to answer the question.
Explanation:
Let x is the first sum, then (24000-x) is the second sum
From I: [(x*6*1)/100] + [((24000-x)*4*1)/100] = 5434
So x can be calculated.
From I: [(x*6*1)/100] = 2 * [((24000-x)*4*1)/100]
So x can be calculated.
- On selling a product, what is the profit % earned?
I. The profit earned on selling the product was Rs 45.
II. Had the product been sold for Rs 555, the profit would have been Rs 50.
Answer & Explanation
(B) If the data in statement II alone is sufficient to answer the question.
Explanation:
From I: We have profit, but CP is needed to calculate profit%
From II: Profit is 55, SP is 555, so CP = 555-55 = 500, so Profit% = 55/500 * 100
- How many children does the group contains?
I. With that total age of all the children in the group to be 240 years, the average age is 15 years.
II. The total age of all the children in the group and the teacher is 264 years. The average age of the children is 5 less than the age of teacher.
Answer & Explanation
(A) If the data in statement I alone is sufficient to answer the question.
Explanation:
From I: no of children = 240/15
From II: total age of all the children/ No of children = average
Teacher’s age = 5 + average
Teacher’s age + total age of all the children = 264
We have 3 equations, with 4 variables which cannot be solved.
- What is the difference between the ages of Y and X?
I. The ratio of the age X to the age of Y is 3 : 2
II. One sixth of X’s age is equal to one fourth of Y’s age.
Answer & Explanation
(D) If the data given in both I and II together are not sufficient to answer the question.
Explanation:
From I: X’ age = 3x, Y’s age = 2x
From II: (1/6) * 3x = (1/4) * 2x. this gives 1/2 = 1/2
So no conclusion.
- What is the total cost of painting a conical flask at the rate of 20 Rs per square metre?
I. The diameter and the slant height of the flask are 14 m and 12 m respectively
II. The area of the base of flask is 526 sq. m and its height is 9 m.
Answer & Explanation
(C) If the data either in statement I alone or statement II alone are sufficient to answer the question.
Explanation:
From I: r = 14/2 = 7m, l = 12m, so cost of painting = 20*(ᴨrl)
From I: ᴨr2 = 526, so r can be calculated, h = 9m, so l = √ r2 + h2, so l can also be calculated.
Cost of painting = 20*(ᴨrl)
- What is the rate of interest on a sum of money?
I. The difference between SI and CI obtained on the sum of money at the end of 2 years at same rate is Rs 80.
II. At the end of 3 years, a total of Rs 3000 is obtained as the CI.
Answer & Explanation
(E) If the data in both the statements I and II together are necessary to answer the question.
Explanation:
From I: Pr2/1002 = 80
From II: 3000 = P [(1 + r/100)2 – 1]
From I and II we have 2 equations in 2 variables which can be solved to find P. - The average age of the employees in a company is 30 years. If in next year 10 employees will retire, what will be the average age then?
I. Age of retirement is 60 years.
E) There are 200 employees in the company at present.
Answer & Explanation
(E) If the data in both the statements I and II together are necessary to answer the question.
Explanation:
From I: The age of 10 employees who will leave the company is 60 each, so their total age is 60*10 = 600
From II: There are 200 employees, and the average age is 30 so their total age becomes 200*30 = 6000
From I if the age of people who are going to leave the company is subtracted, the total age is 6000 – 600 = 5400 which is the total age of remaining 190 employees. So their av. Age = 5400/190 - What is the cost price of the article?
I. The article was bought at 20% discount on the marked price.
II. The article was sold for Rs 2000 with 25% profit on the marked price.
Answer & Explanation
(E) If the data in both the statements I and II together are necessary to answer the question.
Explanation:
Let MP = x
From I: CP = 80/100 * x = 4x/5
From II: SP = 2000, and also SP should be 125/100 * x = 5x/4
So 5x/4 = 2000. Solve x = 1600
Nor from I CP = 4x/5 so CP (4*1600)/5
- In how many hours 5 men can complete a piece of work?
I. 12 men and 15 women can complete a piece of work in 48 hours.
II. 10 men completes one fourth of the work in 4 days working 6 hours per day.
Answer & Explanation
(B) If the data in statement II alone is sufficient to answer the question.
Explanation:
From I: working hours of women need to be known to find it for men.
From II: 10 men completes 1/4 of work in 4*6 = 24 hours
So acc. to M1*H1*W2 = M2*H2*W1
M2 = 5 men whose number of hours is to be found, W2 = 1 because whole work is to be completed by 5 men.
10*24*1 = 5*H2*(1/4). Solve H2 can be calculated.
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